a jogger run 3 miles north and 5.5 miles east . what is the shortest distance back to their starting point
1 answer:
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To Find :
Position vector at time and
.
Solution :
r (t) = 2 (t −7)i + 12t j
Putting t = 5 s and t = 8 s, we get :
r(5) = 2( -2 )i + 60j
r(5) = -4i + 60j
r(8) = 2i + 96j
Now, to find speed differentiating the r(t) w.r.t t :
Hence, this is the required solution.