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Katyanochek1 [597]
3 years ago
15

Which one of the following is true when ds/st =3t^2/2s

Mathematics
1 answer:
Zina [86]3 years ago
7 0
Middle school math!  I actually know how to teach differential calculus to middle schoolers, but I wouldn't start with this example, where we're gonna have to integrate eventually.

We have

\dfrac{ds}{dt} = \dfrac{3t^2}{2s}

We have an odd mix of s and t on the right, which means this probably was an implicit derivative to begin with.  In other words, instead of s as a function of t, we have some equation of s and t that is satisfied.

We move the variables to their respective sides 

2s \ ds = 3t^2 dt

Integrating,

s^2 =t^3 + C

We only need one constant of integration.

I won't bother to write the square root. This is choice D.

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a) 0.984

b) 20 people

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a)

If The probability that a person carries the gene is 0.1, then in a sample of 20 people, 2 should carry the gene.

Now, we want to know how many samples there are with this property.

Since we have 20 elements where 18 are alike (do not carry the gene) and 2 are alike (carry the gene), we have to compute the number of permutations of 20 elements in which 18 are alike and 2 are alike. This number is

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(1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(1,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

where 1=carries the gene, 0=does not carry the gene.

So there are 190-3 = 187 elements in which the first 3 elements have no 2 carriers, hence the probability that 4 or more people will have to be tested until 2 of them with the gene are detected is 187/190 = 0.984 (98.4%) rounded to three decimal places.

b)

Given that the probability that a person carries the gene is 0.1, then in a sample of 20 people, 20*0.1 = 2 should carry the gene.

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