All categories

2 years ago

How can you use expressions to find the percent of a number?

Mathematics

2 answers:

luda_lava [24]2 years ago

8 0

Answer:

See below

Step-by-step explanation:

x% of y is found as:

1% of y ⇒ y*1/100 = 0.01y
x% of y ⇒ x*0.01y = 0.01xy

So the answer is:

0.01xy

netineya [11]2 years ago

4 0

Answer:

Review how to find the percent of an amount to find the percent of an amount or of a whole we write

Step-by-step explanation:

You might be interested in

Which transformations will produce similar, but not congruent, figures?

n200080 [17]

A, because anything with a dilation will not be congruent as the original PQR :))

7 0

3 years ago

Read 2 more answers

Solve the equation f/3+22=17

andrezito [222]

1) f/3 + 22 = 17

2) f/3 + 22 - 22 = 17 - 22

= f/3 = -5

3) 3 • f/3 = 3(-5)

= f = 3(-5)

= f = -15

Your answer would be f = -15

:)

4 0

3 years ago

Read 2 more answers

How do I find the integral ∫10(x−1)(x2+9)dxint10/((x-1)(x^2+9))dx ?

defon

$\int\frac{10}{(x-1)(x^2+9)}\ dx=(*)\\\\\frac{10}{(x-1)(x^2+9)}=\frac{A}{x-1}+\frac{Bx+C}{x^2+9}=\frac{A(x^2+9)+(Bx+C)(x-1)}{(x-1)(x^2+9)}\\\\=\frac{Ax^2+9A+Bx^2-Bx+Cx-C}{(x-1)(x^2+9)}=\frac{(A+B)x^2+(-B+C)x+(9A-C)}{(x-1)(x^2+9)}\\\Updownarrow\\10=(A+B)x^2+(-B+C)x+(9A-C)\\\Updownarrow\\A+B=0\ and\ -B+C=0\ and\ 9A-C=10\\A=-B\ and\ C=B\to9(-B)-B=10\to-10B=10\to B=-1\\A=-(-1)=1\ and\ C=-1$

$(*)=\int\left(\frac{1}{x-1}+\frac{-x-1}{x^2+9}\right)\ dx=\int\left(\frac{1}{x-1}-\frac{x+1}{x^2+9}\right)\ dx\\\\=\int\frac{1}{x-1}\ dx-\int\frac{x+1}{x^2+9}\ dx=\int\frac{1}{x-1}-\int\frac{x}{x^2+9}\ dx-\int\frac{1}{x^2+9}\ dx=(**)\\\\\#1\ \int\frac{1}{x-1}\ dx\Rightarrow\left|\begin{array}{ccc}x-1=t\\dx=dt\end{array}\right|\Rightarrow\int\frac{1}{t}\ dt=lnt+C_1=ln(x-1)+C_1$

$\#2\ \int\frac{x}{x^2+9}\ dx\Rightarrow \left|\begin{array}{ccc}x^2+9=u\\2x\ dx=du\\x\ dx=\frac{1}{2}\ du\end{array}\right|\Rightarrow\int\left(\frac{1}{2}\cdot\frac{1}{u}\right)\ du=\frac{1}{2}\int\frac{1}{u}\ du\\\\\\=\frac{1}{2}ln(u)+C_2=\frac{1}{2}ln(x^2+9)+C_2$

$\#3\ \int\frac{1}{x^2+9}\ dx=\int\frac{1}{x^2+3^2}\ dx=\frac{1}{3}tan^{-1}\left(\frac{x}{3}\right)+C_3\\\\therefore:\\\\\#1;\ \#2;\ \#3\Rightarrow(**)=ln(x-1)+C_1-\frac{1}{2}ln(x^2+9)+C_2-\frac{1}{3}tan^{-1}\left(\frac{x}{3}\right)+C_3$

$\boxed{=ln(x-1)-\frac{1}{2}ln(x^2+9)-\frac{1}{3}tan^{-1}\left(\frac{x}{3}\right)+C}$

4 0

4 years ago

Write the following as an algebraic expression. Then simplify.

Ratling [72]

The sum of three even consecutive integers if the first integer is y will be 3y + 6.

First integer = y

Second integer = y + 2

Third integer = y + 4

Therefore, based on the expressions given above, the sum of the three integers will be:

= y + y +2 + y + 4

= 3y + 6

Therefore, the sum will be 3y + 6.

Read related link on:

brainly.com/question/24733295

5 0

2 years ago

Ty bought a pair of jeans at a 25% off sale. He paid $22.50 before tax for the jeans. What was the original price of the jeans

TEA [102]

$30

You do : 22.50/0.75
because when you take off 25% you times 0.75 and 22.50 together. To undo that you divide

7 0

3 years ago