Answer: AB = 6
Step-by-step explanation:
If CD = 12 , AC also = 12
B is the midpoint of AC so one side = 6
AB is one side of AC , so AB = 6
I am not a professional, I am simply using prior knowledge!
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Answer:

Step-by-step explanation:
Look at the picture.
ΔADC and ΔCDB are similar. Therefore the sides are in proportion:

We have

Substitute:
<em>cross multiply</em>


For x use the Pythagorean theorem:

Answer:
Step-by-step explanation:
differences
Answer:
3n+16
Step-by-step explanation:
three times: (3) a number n +16
(3)n+16 or 3xn+16
3n+16