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kirill [66]
3 years ago
14

Simplify 3 square root of 125

Mathematics
1 answer:
RSB [31]3 years ago
6 0
We have:

3 \sqrt{125}
3 \sqrt{25*5}
15 \sqrt{5}

As 5 has no perfect square factors, we have completely simplified this expression.
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The formula for the hypotenuse of a right triangle with legs of length a and b is shown.
fomenos

Answer: b=\sqrt{c^{2}-a^{2}}

Step-by-step explanation:

To solve the exercise you must solve for b from the formula for the hypotenuse, as you can see below:

- Square both sides of the equation as following:

c^{2}=(\sqrt{a^{2}+b^{2}})^{2}

- Now you must subtract a² from each side of the equation, then you obtain:

c^2-a^{2}=a^{2}-a^{2}+b^{2}

c^2-a^{2}=b^{2}

- Apply square root to both sides:

\sqrt{b^{2}}=\sqrt{c^{2}-a^{2}}

Then:

b=\sqrt{c^{2}-a^{2}}

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3 years ago
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Here is a sketch of y=x^2+bx+c The curve intersects
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Answer:

y = 18  and  x = -2

Step-by-step explanation:

y = x^2+bx+c   To find the turning point, or vertex, of this parabola, we need to work out the values of the coefficients b and c. We are given two different solutions of the equation. First, (2, 0).  Second, (0, -14). So we have a value (-14) for c. We can substitute that into our first equation to find b. We can now plug in our values for b and c into the equation to get its standard form. To find the vertex, we can convert this equation to vertex form by completing the square. Thus, the vertex is (4.5, –6.25). We can confirm the solution graphically     Plugging in  (2,0) :

y=x2+bx+c  

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y=4+2b+c  

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Plugging in  (0,−14) :

y=x2+bx+c  

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−16=0+b+c  

b=16−c  

Now that we have two equations isolated for  b , we can simply use substitution and solve for  c .   y=x2+bx+c  16 + 2 = y   y = 18  and  x = -2

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3 years ago
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Answer:

x=12

Step-by-step explanation:

5x+4+64+52=180

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5x+4+64+52-(180)=0

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We move all terms containing x to the left, all other terms to the right

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