In triangle ABC, m angle A = 30° and m angle B = 60°. Matches these in the order from smallest to largest. AB, BC, AC
2 answers:
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Refer to the graph shown below. It confirms that points A, B and P are
collinear.
Calculate the length of AP (as a).
a = √[(6 - 2)² + (11 - 3)²]
= 8.9443
Calculate the length of BP (as b).
b = √[(8 - 6)² + (15 - 11)²]
= 4.4721
Calculate ratio a/b.
a/b = 8.9443/4.4721 = 2
Therefore P partitions AB in a 2:1 ratio so that AP = 2*BP.
Answer: 2:1 ratio.
collinear.
Calculate the length of AP (as a).
a = √[(6 - 2)² + (11 - 3)²]
= 8.9443
Calculate the length of BP (as b).
b = √[(8 - 6)² + (15 - 11)²]
= 4.4721
Calculate ratio a/b.
a/b = 8.9443/4.4721 = 2
Therefore P partitions AB in a 2:1 ratio so that AP = 2*BP.
Answer: 2:1 ratio.
Recall your d = rt, distance = rate * time
so... one train goes west and the goes the opposite way... alrite... so... notice, by the time 338 miles have been covered by both, it will have been "t" hours, and whatever "t" is, is the same amount of time the westbound train has been running as well as the eastbound train has been running.
now, let's say, since by "t" hours they've covered 338 altogether, so, if the westbound train has covered say "d" miles, then the eastbound train would have covered the slack from 338 and d, that is, "338 - d".
so, 2hours and 36 minutes.
so... one train goes west and the goes the opposite way... alrite... so... notice, by the time 338 miles have been covered by both, it will have been "t" hours, and whatever "t" is, is the same amount of time the westbound train has been running as well as the eastbound train has been running.
now, let's say, since by "t" hours they've covered 338 altogether, so, if the westbound train has covered say "d" miles, then the eastbound train would have covered the slack from 338 and d, that is, "338 - d".
so, 2hours and 36 minutes.