Solution :
check_palindrome
lower_
_string
string
_lower()
Let stack = new Stack()
Let queue = new Queue();
for each character c in lower_case_string:
stack.push(c);
queue.enqueue(c);
let isPalindrome = true;
while queue is not empty {
if (queue.remove().equals(stack.pop())) {
continue;
} else {
isPalindrome=false;
break while loop;
}
}
return isPalindrome
Input = aabb
output = true
input =abcd
output = false
Answer:
B) multi user -multi tasking
Answer:
# include <iostream>
#include<stdio.h>
using namespace std;
bool IsLeapYear(int y)
int main()
{
int y;
cout<<"Enter the Year to check Leap or Not"<<endl;
cin>>y;
IsLeapYear(int y);
getch();
}
bool IsLeapYear(int y)
{
if (y%4==0)
{
if (y%100==0)
{
if (y%400==0 )
{
cout<"The year is leap Year";
}
else
{
cout<<" The year is not Leap Year";
}
}
else
{
cout<<"The year is Leap Year" ;
}
}
else
{
cout<<"The year is not Leap Year";
}
}
Explanation:
In this program a function has been defined named as IfLeapYear, to check that whether the entered year is leap year or not. An year taken as integer data type named as y to enter the year to check. If the year is divisible by 4 but not divisible by 100 is the leap year. If the year is divisible by 4, divisible by 100 and also divisible by 400 is the century year and is also the leap year.
To check all the statements, Nested if-else conditions has been used to check multiple requirements of the leap year.
Answer:
The correct answer is E. MP3
Explanation:
MP3 (formally MPEG-1 Audio Layer III or MPEG-2 Audio Layer III) is a coding format for digital audio. MP3 as a file format commonly designates files containing an elementary stream of MPEG-1 audio and video encoded data, without other complexities of the MP3 standard. The MP3 format makes it possible to compress a song into a file small enough to be uploaded, downloaded, emailed, and stored on a hard drive.
