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yKpoI14uk [10]
3 years ago
14

Does anyone watch The Office?

Computers and Technology
1 answer:
kap26 [50]3 years ago
5 0

Answer:

12 times

Explanation:

It's amazing

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What are two advantages of a pay-for-use online conferencing service compared to a free service? (Choose two)
tester [92]

Answer:

Provision of both audio and video

,dedicated support

Explanation:

Free services are not dedicated digital lines so there is no guarantee of high-quality sound or a reliable connection during the call. Some common issues  are background noises, crackling, echoes, distortion, quietness and drop-outs.Free services also don't offer dedicated support so if anything goes wrong there's nobody available to help you. Any of these problems can ruin the productivity and flow of your meeting.

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3 years ago
CHANGE POSITION OF SONG Enter song's current position: Enter new position for song: "Peg" moved to position 3 JAMZ PLAYLIST MENU
hichkok12 [17]

Answer:

Answers can be found below

Explanation:

port java.util.Scanner;

public class Playlist {

String title;

SongEntry head;

public Playlist(String title) {

this.title = title;

this.head = null;

}

public static void main(String[] args) {

Scanner scanner = new Scanner(System.in);

System.out.println("Enter the playlist's title:");

String title = scanner.nextLine();

Playlist playList = new Playlist(title);

String option;

do {

option = playList.printMenu(scanner);

switch (option) {

case "a":

playList.addSong(scanner);

break;

case "d":

playList.removeSong(scanner);

break;

case "c":

playList.changePosition(scanner);

break;

case "s":

playList.outputSongByArtist(scanner);

break;

case "t":

playList.outpuTotalTime();

break;

case "o":

playList.outputFullPlayList();

break;

case "q":

System.out.println("QUIT");

break;

default:

System.out.println("please enter a valid option");

}

} while (!option.equals("q"));

}

public String printMenu(Scanner scanner) {

System.out.println(this.title + " PLAYLIST MENU");

System.out.println("a - Add song");

System.out.println("d - Remove song");

System.out.println("c - Change position of song");

System.out.println("s - Output songs by specific artist");

System.out.println("t - Output total time of playlist (in seconds)");

System.out.println("o - Output full playlist");

System.out.println("q - Quit");

System.out.println("Choose an option:");

String input = scanner.nextLine();

return input;

}

public void outputFullPlayList() {

if (head == null) {

System.out.println("Playlist is empty");

} else {

SongEntry tempNode = head;

while (tempNode != null) {

tempNode.printPlaylistSongs();

tempNode = tempNode.getNextNode();

}

}

}

public void addSong(Scanner scanner) {

System.out.println("ADD SONG");

System.out.println("Enter song's unique ID:");

String uniqueId = scanner.nextLine();

System.out.println("Enter song's name:");

String songName = scanner.nextLine();

System.out.println("Enter artist's name:");

String artistName = scanner.nextLine();

System.out.println("Enter song's length (in seconds):");

int length = Integer.parseInt(scanner.nextLine());

SongEntry song = new SongEntry(uniqueId, songName, artistName, length);

if (head == null) {

head = song;

} else {

SongEntry tempNode = head;

while (tempNode.getNextNode() != null) {

tempNode = tempNode.getNextNode();

}

tempNode.insertAfter(song);

}

}

public void removeSong(Scanner scanner) {

System.out.println("REMOVE SONG");

System.out.println("Enter song's unique ID:");

String uniqueId = scanner.nextLine();

SongEntry tempNode1 = head;

SongEntry tempNode2 = head;

while (tempNode1 != null) {

if (tempNode1.getUniqueID().equals(uniqueId)) {

if (tempNode1.getUniqueID().equals(head.getUniqueID())) {

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3 years ago
What are two fundamental components of data structures?
Fed [463]
Organization and access method.

Hope this helped! :)

- Jujufire
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3 years ago
How is a WAN different from a LAN?
RSB [31]

<em>A</em><em> </em><em> </em><em>WAn</em><em> </em><em>(</em><em> </em><em>Wide</em><em> </em><em>Area</em><em> </em><em>Network</em><em> </em><em>)</em><em> </em><em>is</em><em> </em><em>made</em><em> </em><em>up</em><em> </em><em>of</em><em> </em><em>LANS</em><em> </em><em>(</em><em> </em><em>Local</em><em> </em><em>Area</em><em> </em><em>Network</em><em>)</em><em>…</em><em>…</em><em>…</em><em>…</em>

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2 years ago
.true or false? one disadvantage of cloudware is that it is never free<br> A. true<br> B. false
ser-zykov [4K]

Answer:

true

Explanation:

cloudware is used for many reasons and It is sometimes too much of an expense to the company

7 0
3 years ago
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