In a square, one pair of opposite sides was made 50% longer and the other pair of opposite sides was made 50% shorter.

Have I been solving these equations correctly?

Tresset [83]

14)

2(-3)² => 2(-3)(-3) => 2*9 = > 18

27+18-11 => 27 + 7 = > 34.

16)

$\bf p(x)=\cfrac{x^2-4}{2x+1}\implies p(-8)=\cfrac{(-8)^2-4}{2(-8)+1}\implies p(-8)=\cfrac{64-4}{-16+1} \\\\\\ p(-8)=\cfrac{60}{-15}\implies p(-8)=-4$

17)

$\bf h(x)=3\cdot 9^x\implies h(-2)=3\cdot 9^{-2}\implies h(-2)=3\cdot \cfrac{1}{9^2} \\\\\\ h(-2)=\cfrac{3}{9^2}\implies h(-2)=\cfrac{3}{81}\implies h(-2)=\cfrac{1}{27}$

4 0

3 years ago

Help with number two

BabaBlast [244]

Answer:

y = -2x+1

Step-by-step explanation:

We have a point and a slope, so we can use the point slope form of a line

y-y1 = m(x-x1) where m is the slope and (x1,y1) is the point

y-3 = -2(x--1)

y-3=-2(x+1)

Distribute the 2

y-3 = -2x-2

Add 3 to each side

y-3+3 = -2x-2+3

y = -2x+1

This is in slope intercept form

7 0

2 years ago

Imagine that you are doing an exhaustive study on the children in all of the daycares in your school district. You are particula

alisha [4.7K]

Answer: The difference between M and mu is due to the sampling error is <u>-6.59 .</u>

Step-by-step explanation:

As per given:

in population, the average number of minutes spent in active play on weekends is μ = 65.87

In sample, the average number of minutes the children spend in active play on weekends is M = 59.28

Now, the difference between M and μ is due to the sampling error is M- μ

= 59.28 - 65.87

= -6.59

So, the difference between M and mu is due to the sampling error is <u>-6.59 .</u>

8 0

3 years ago

Please answer correctly !!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!!!

lisabon 2012 [21]

Answer:

x = 4

Step-by-step explanation:

The parallel segment divides the 2 sides of the triangle proportionally, that is

$\frac{x}{8}$ = $\frac{6}{12}$ ( cross- multiply )

12x = 48 ( divide both sides by 12 )

x = 4

5 0

2 years ago

Read 2 more answers

Use the diagram to complete the statement. Triangle J K L is shown. Angle K J L is a right angle. Angle J K L is 52 degrees and

zzz [600]

Answer:

$\bold{sin(38^\circ)=cos(52^\circ)}$

Step-by-step explanation:

Given that $\triangle KJL$ is a right angled triangle.

$\angle JKL = 52^\circ\\\angle KLJ = 38^\circ$

and

$\angle KJL = 90^\circ$

Kindly refer to the attached image of $\triangle KJL$ in which all the given angles are shown.

To find:

sin(38°) = ?

a) cos(38°)

b) cos(52°)

c) tan(38°)

d) tan(52°)

Solution:

Let us use the trigonometric identities in the given $\triangle KJL$ .

We have to find the value of sin(38°).

We know that sine trigonometric identity is given as:

$sin\theta =\dfrac{Perpendicular}{Hypotenuse}$

$sin(\angle JLK) = \dfrac{JK}{KL}\\OR\\sin(38^\circ) = \dfrac{JK}{KL}$ ....... (1)

Now, let us find out the values of trigonometric functions given in options one by one:

$cos\theta =\dfrac{Base}{Hypotenuse}$

$cos(\angle JLK) = \dfrac{JL}{KL}\\OR\\cos(38^\circ) = \dfrac{JL}{KL}$ ....... (2)

By (1) and (2):

sin(38°) $\neq$ cos(38°).

$cos(\angle JKL) = \dfrac{JK}{KL}\\OR\\cos(52^\circ) = \dfrac{JK}{KL}$ ...... (3)

Comparing equations (1) and (3):

we get the both are same.

$\therefore \bold{sin(38^\circ)=cos(52^\circ)}$

6 0

2 years ago