3 years ago

In a square, one pair of opposite sides was made 50% longer and the other pair of opposite sides was made 50% shorter.

Mathematics

1 answer:

maria [59]3 years ago

4 0

I answered the last one. I figured out what I did wrong.

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Factor 7(h+k)^2-21(h+k)

VARVARA [1.3K]

7(h+k)(h+k- 3) if this is the answer you're looking for this is what I got so. Good luck

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3 years ago

Factor completely 3bx2 − 9x3 − b + 3x. (b − 3x)(3x2 − 1) (b + 3x)(3x2 + 1) (b + 3x)(3x2 − 1) Prime

Daniel [21]

$3bx^2-9x^3-b+3x=\boxed{3x^2}\cdot b-\boxed{3x^2}\cdot3x\fbox{-1}\cdot b\fbox{-1}\cdot (-3x)\\\\=\boxed{3x^2}(b-3x)\fbox{-1}(b-3x)=\boxed{(b-3x)(3x^2-1)}\\\\completely:\\use:a^2-b^2=(a-b)(a+b)\to3x^2-1=(x\sqrt3)^2-1^2=(x\sqrt3-1)(x\sqrt3+1)$
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3 years ago

Read 2 more answers

A rectangle's length, x, is 2 meters greater than its width. If the perimeter of the rectangle is greater than 112 meters, what

Harman [31]

Answer:

The possible length is greater than 29 meters.

Step-by-step explanation:

If the length is x then the width is x - 2 m.

So the perimeter is 2x + 2(x - 2) = 4x - 4 m.

4x - 4 > 112

4x > 116