Answer:
The probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.
Step-by-step explanation:
Let the random variable <em>X</em> denote the water depths.
As the variable water depths is continuous variable, the random variable <em>X</em> follows a continuous Uniform distribution with parameters <em>a</em> = 2.00 m and <em>b</em> = 7.00 m.
The probability density function of <em>X</em> is:
Compute the probability that a randomly selected depth is between 2.25 m and 5.00 m as follows:
![=\frac{1}{5.00}\int\limits^{5.00}_{2.25} {1} \, dx\\\\=0.20\times [x]^{5.00}_{2.25} \\\\=0.20\times (5.00-2.25)\\\\=0.55](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B5.00%7D%5Cint%5Climits%5E%7B5.00%7D_%7B2.25%7D%20%7B1%7D%20%5C%2C%20dx%5C%5C%5C%5C%3D0.20%5Ctimes%20%5Bx%5D%5E%7B5.00%7D_%7B2.25%7D%20%5C%5C%5C%5C%3D0.20%5Ctimes%20%285.00-2.25%29%5C%5C%5C%5C%3D0.55)
Thus, the probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.
I'm assuming there is a graph with both functions plotted. The solution would be the point at which these two functions intersect. That coordinates of x and y for that point will yield the solutions for x and y that solve the system of equations.
Answer:
200,000 m
Step-by-step explanation:
We will multiply the length of the ant by the number of ants to find out how long the line is.
10 million is 10 with 6 zeros
20 * 10 ^-3 move the decimal 3 places to the left
20. * 10 ^-3 = .02
.02 * 10000000
200000
Answer:
495.43
Step-by-step explanation:
Formula:
a^2+b^2=c^2
c^2: Is the hypotenuse.
For a^2 and b^2, you have to multiply both it by its self.
Then, add both.
Next, you square root it.
Example:
a^2+b^2=c^2
14^2+7^2=c^2
196+49=c^2
245=c^2
15.64=c^2
