17 = -13 - 8x .....add 13 to both sides
13 + 17 = -8x
30 = -8x...now divide both sides by -8
-30/8 = x...reduce
- 15/4 or -3 3/4 = x <===
Answer:
1 a.) 2t – 2
1 b.) –9z + 4
2 a.) –2v + 3
2 b.) –13k – 9
3 a.) 7w − 2
3 b.) 10s
4 a.) 5
4 b.) –3p + 11
5 a.) –29x + 9
b.) 15v – 60x – 2
a.) 25n + 2
b.) –15n
a.) –71x + 4
b.) –15b
Step-by-step explanation:
- <em>NOTE: I am kind of confused about the way this question is formatted, so I tried to answer everything I could decipher.</em>
1 a.) –2t + 5t – 2 – t → 2t – 2
1 b.) –5z + 4 – 4z → –9z + 4
2 a.) 8v + 3 – 10v → –2v + 3
2 b.) –6 – 6k – 3 – 7k → –13k – 9
3 a.) –6 – 3w + 4 + 10w → 7w − 2
3 b.) 9s + s → 10s
4 a.) 6 + 8b – 1 – 8b → 5
4 b.) 1p + 6 + 5 – 4p → –3p + 11
5 a.) 4x – 3x + 9 – 6x 5 → –29x + 9
b.) 9v + 6v – 2 – 10x 6 → 15v – 60x – 2
a.) n + 2 – (–4)n 6 → 25n + 2
b.) 6n – 3n 7 → –15n
a.) –4x – 4x + 4 – 9x 7 → –71x + 4
b.) –9b + (–6)b → –15b
If you divide negative by positive it will be negative.
If you divide positive by negative it will be negative.
If you divide 2 negatives you get a positive.
I hope this helps :)
|-5| is greater than |-2| because |-5| is 5 and |-2| is 2 and 5 is greater than 2.
<span><span><span><span><span>(5)</span><span>(<span>−3</span>)</span></span>−<span><span>(4)</span><span>(<span>−3</span>)</span></span></span>−3</span>−<span><span>(3)</span><span>(<span>−3</span>)</span></span></span><span>=<span><span><span><span>−15</span>−<span><span>(4)</span><span>(<span>−3</span>)</span></span></span>−3</span>−<span><span>(3)</span><span>(<span>−3</span>)</span></span></span></span><span>=<span><span><span><span>−15</span>−<span>(<span>−12</span>)</span></span>−3</span>−<span><span>(3)</span><span>(<span>−3</span>)</span></span></span></span><span>=<span><span><span>−3</span>−3</span>−<span><span>(3)</span><span>(<span>−3</span>)</span></span></span></span><span>=<span><span>−6</span>−<span><span>(3)</span><span>(<span>−3</span>)</span></span></span></span><span>=<span><span>−6</span>−<span>(<span>−9</span>)</span></span></span><span>=<span>3</span></span>
