Answer:
Step-by-step explanation:
i dont know sorry
<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
Answer:
y < x - 4
Step-by-step explanation:
First, move the x over to the other side by subtracting x from both sides. This will get you -y > -x + 4.
Divide both sides by -1 to get rid of the -1 in front of y. Since this is an inequality, dividing or multiplying by a negative number means that you have to flip the sign. We are dividing by a negative number, so flip > to <. The signs on both sides change to get y < x - 4.
I think answer should be the first one please give me brainlest I hope this helps let me know if it’s correct or not okay thanks bye
