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3 years ago

If x-12√x + 36 = 0 what is the value of x A. 6 B. 6^2 C. 6^3 D. 6^4

Mathematics

1 answer:

Snowcat [4.5K]3 years ago

8 0

Let
$\sqrt{x} = a$
then you will have a^2-12a+36=0 and then you can just factor to find a

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3 years ago

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BabaBlast [244]

Hey!

Weight of small box = 5 lb. x no. of small boxes total weight = 5*x

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5x + 12y Less than or equal to 80.

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Step-by-step explanation:

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2 years ago

At a grocery store a cake was on sale for 22% off if the original price of the cake was c what is the sale price in terms of c

Harlamova29_29 [7]

Answer:

( 39/50 ) * c

Step-by-step explanation:

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3 years ago

Read 2 more answers

The midpoint of \overline{\text{AB}}AB is M(-6, -4)M(−6,−4). If the coordinates of AA are (-4, -3)(−4,−3), what are the coordina

valentina_108 [34]

Answer:

The coordinates of B is (-8,-5).

Step-by-step explanation:

The midpoint of line AB is M. The coordinate of M is (-6,-4).

The coordinates of A is (-4,-3)

We need to find the mid point of B.

If M(x,y) is the midpoint of the coordinates (x₁,y₁) and (x₂,y₂). The mid point theorem is used as follows :

$M(x,y)=(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})$

Let the mid point of B is (x₂,y₂). Put (x,y) = (-6,-4), (x₁,y₁) = (-4,-3).

$(-6,-4)=(\dfrac{-4+x_2}{2},\dfrac{-3+y_2}{2})\\\\\dfrac{-4+x_2}{2}=-6\ \text{and}\ \dfrac{-3+y_2}{2}=-4\\\\-4+x_2=-12\ \text{and}\ -3+y_2=-8\\\\x_2=-12+4\ \text{and}\ y_2=-8+3\\\\x_2=-8\ \text{and}\ y_2=-5$

So, the coordinates of B is (-8,-5).

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2 years ago