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2 years ago

9

Help solve w(5w^3)^-2 / w^-4

1 answer:

Bond [772]2 years ago

3 0

Start with the exponents, 3 and -2, you multiply them together so you get -6 so its w(w^-6)/w^-4 and then you do wx5w^-6 which is 5w^-4 bc im pretty sure you multiply it to 5w and thats 5w squared so you just add it and so it becomes 5w^-4/5w^-4 and you can simplify that

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For this case we have the following expression:

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For this case we can apply the following property:

$a log_c (b) = log_c (b^a)$

And we can rewrite the following expression like this:

$2 ln(x) = ln(x^2)$

And we can rewrite like this our expression:

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Now we can use the following property:

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And we got this:

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And now we can apply the following property:

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And that would be our final answer on this case.

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3 years ago