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ludmilkaskok [199]

4 years ago

6

A light bulb manufacturing machine produces 72 light bulbs per minute. How much time would it take to make 5400 light bulbs?

1 answer:

snow_tiger [21]4 years ago

3 0

(5400 bulbs)/(72 bulbs/min) = 75 min

It would take 75 minutes for the machine to make 5400 light bulbs.

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anne picks a 4-digit number the first number is not 0 the four digit number is a multiple of 5 how many different 4-digit number

Gala2k [10]

The first digit of a number can be 1-9. The 2nd and the 3rd digit can be 1-10. The last digit can be 0 or 5 ( 2 numbers ):
9 * 10 * 10 * 2 = 1,800
She could pick 1,800 different 4-digit numbers.

8 0

4 years ago

What is the area of 1/2x7(4+2)

solong [7]

3x^7 will be your answer
hope this helps!

8 0

3 years ago

What is 6 3/4+1 5/8=

lara31 [8.8K]

Answer:

Step-by-step explanation:

$6\frac{3}{4}+1\frac{5}{8}=6+1+\frac{3}{4}+\frac{5}{8}\\\\=7+\frac{3*2}{4*2}+\frac{5}{8}\\\\=7+\frac{6}{8}+\frac{5}{8}=7+\frac{6+5}{8}\\=7+\frac{11}{8}=7+1\frac{3}{8}=7+1+\frac{3}{8}\\\\=8\frac{3}{8}$

7 0

4 years ago

Assignment due today Q-Q<br> 9 1/2=k/9

nikdorinn [45]

$\huge\mathfrak\blue{answer}$

$= q - \frac{q91}{2} = \frac{k}{9}$

$\blue{switch \: sides}$

$= \frac{k}{9} = q - \frac{q91}{2}$

$\blue{multiply \: 9 \: both \: sides}$

$= \frac{9k}{9} = 9q - 9 \: . \: \frac{q91}{2}$

$\blue{lastly \: simplify}$

$=\underline {k = 9q - \frac{{9q}^{91} }{2} }$

(mark me brainliest if you're satisfied)

3 0

3 years ago

A small town has 2000 inhabitants. At 8 AM, 160 people have heard a rumor. By noon half the town has heard it. At what time will

QveST [7]

Answer:

3:36 PM

Step-by-step explanation:

Let fraction (y) of the people that heard the rumor , the differential equation that is satisfied by the by y is,

$\frac{dy}{dt} = ky(1-y)$

Solving the differential equation,

$y(t) = \frac{y_{o}}{[y_{o} + (1 + y_{o})e^{-kt}]}$

The total number of inhabitants of the town = 2000

The number of people that heard the rumor = 160

At 8 AM, let t = 0,

$y(0) = \frac{160}{2000}$

= 0.08

By noon, half of the town as heard the rumor.

Then,

$y(4) = \frac{1}{2}$

Therefore,

$\frac{1}{2} = \frac{0.08}{[0.08 + (1 - 0.08)e^{-4k}]}$

$\frac{0.08}{[0.08 + 0.92e^{-4k}]} = \frac{1}{2}$

$0.08 + 0.92e^{-4k} = 0.16$

$0.92e^{-4k} = 0.16 - 0.08$

$0.92e^{-4k} = 0.08$

$e^{-4k} = \frac {0.08}{0.92}$

$k = - \frac{1}{4} In(\frac {0.08}{0.92})$

k ≈ 0.06106

Calculating time, t when y(t) = 90%

⇒ y(t) = 0.9

$\frac{0.08}{[0.08 + 0.92e^{-0.06106t}]} =0.9$

$0.08 + 0.92e^{-0.06106t} = \frac {0.9}{0.08}$

$0.08 + 0.92e^{-0.06106t} = 0.089$

$0.92e^{-0.06106t} = 0.089 - 0.08$

$0.92e^{-0.06106t} = 0.0089$

$t = - \frac{1}{0.06106}In (\frac{0.0089}{0.92})$

t = 7.59 hours

⇒ 7 hours 36 minutes

From 8 A.M. plus 7 hours 36 minutes = 3:36 PM

At 3:36 PM will 90% of the population have heard the rumor

7 0

3 years ago