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3 years ago

A light bulb manufacturing machine produces 72 light bulbs per minute. How much time would it take to make 5400 light bulbs?

Mathematics

1 answer:

snow_tiger [21]3 years ago

3 0

(5400 bulbs)/(72 bulbs/min) = 75 min

It would take 75 minutes for the machine to make 5400 light bulbs.

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HELP PLEASE You're taking a scenic road trip down CA-Highway 1 from San Jose, California, to Los Angeles. You plan to split the

Savatey [412]

Answer:

((I do not have the answers for one, two, or four))

3.)

•What do you know?

-It’s about 425 miles from San Jose to Los Angeles and 320 miles from San Jose to Santa Barbara.

•What do you want to find out?

-How many miles it is from Santa Barbara to Los Angeles.

•What kind of answer do you expect?

-If using variable, I expect that I will get the number of miles from one city to the other.

5.)

425 = 320 + X

6.)

425 = 320 + X

Subtract 320 from both sides.

7.)

X = 105

From Santa Barbra to Los Angeles it is 105 miles.

8.)

320 + 105 = 425

3 0

3 years ago

For which function does f (-8) = f (8) ?

nignag [31]

Answer:

Step-by-step explanation:

Can you give me more information on the question, so i can make sure that i give you the correct answer . I think its A but not totally for sure

8 0

3 years ago

Problem 4: Let F = (2z + 2)k be the flow field. Answer the following to verify the divergence theorem: a) Use definition to find

Viktor [21]

Given that you mention the divergence theorem, and that part (b) is asking you to find the downward flux through the disk $x^2+y^2\le3$ , I think it's same to assume that the hemisphere referred to in part (a) is the upper half of the sphere $x^2+y^2+z^2=3$ .

a. Let $C$ denote the hemispherical <u>c</u>ap $z=\sqrt{3-x^2-y^2}$ , parameterized by

$\vec r(u,v)=\sqrt3\cos u\sin v\,\vec\imath+\sqrt3\sin u\sin v\,\vec\jmath+\sqrt3\cos v\,\vec k$

with $0\le u\le2\pi$ and $0\le v\le\frac\pi2$ . Take the normal vector to $C$ to be

$\vec r_v\times\vec r_u=3\cos u\sin^2v\,\vec\imath+3\sin u\sin^2v\,\vec\jmath+3\sin v\cos v\,\vec k$

Then the upward flux of $\vec F=(2z+2)\,\vec k$ through $C$ is

$\displaystyle\iint_C\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^{\pi/2}((2\sqrt3\cos v+2)\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm dv\,\mathrm du$

$\displaystyle=3\int_0^{2\pi}\int_0^{\pi/2}\sin2v(\sqrt3\cos v+1)\,\mathrm dv\,\mathrm du$

$=\boxed{2(3+2\sqrt3)\pi}$

b. Let $D$ be the disk that closes off the hemisphere $C$ , parameterized by

$\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath$

with $0\le u\le\sqrt3$ and $0\le v\le2\pi$ . Take the normal to $D$ to be

$\vec s_v\times\vec s_u=-u\,\vec k$

Then the downward flux of $\vec F$ through $D$ is

$\displaystyle\int_0^{2\pi}\int_0^{\sqrt3}(2\,\vec k)\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv=-2\int_0^{2\pi}\int_0^{\sqrt3}u\,\mathrm du\,\mathrm dv$

$=\boxed{-6\pi}$

c. The net flux is then $\boxed{4\sqrt3\pi}$ .

d. By the divergence theorem, the flux of $\vec F$ across the closed hemisphere $H$ with boundary $C\cup D$ is equal to the integral of $\mathrm{div}\vec F$ over its interior:

$\displaystyle\iint_{C\cup D}\vec F\cdot\mathrm d\vec S=\iiint_H\mathrm{div}\vec F\,\mathrm dV$

We have

$\mathrm{div}\vec F=\dfrac{\partial(2z+2)}{\partial z}=2$

so the volume integral is

$2\displaystyle\iiint_H\mathrm dV$

which is 2 times the volume of the hemisphere $H$ , so that the net flux is $\boxed{4\sqrt3\pi}$ . Just to confirm, we could compute the integral in spherical coordinates:

$\displaystyle2\int_0^{\pi/2}\int_0^{2\pi}\int_0^{\sqrt3}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=4\sqrt3\pi$

4 0

3 years ago

$57.66 is 70% of what total number?

Paha777 [63]

Answer:

74.958

Step-by-step explanation:

Because 57.66 added 30 percent is equal to 74.958

7 0

3 years ago

Consider the system of equations.

anzhelika [568]

Answer: You can multiply the top equation by -1 to eliminate the x variable.

And the solution is (2,4/3) in case you need it.

Step-by-step explanation:

2x + 3y = 8

2x + 6y = 12

If you multiply the upper equation or down equation by one, you will be able to eliminate the x variable.

-1( 2x + 3y) = -1(8) New equation: -2x -3y = -8.

Add the new equation you got by multiplying the top equation by -1 to the bottom equation.

Add them: -2x -3y = -8

2x + 6y = 12

3y = 4

y = 4/3

You can now input the value for y into the one of the equations and solve for x.

-2x - 3(4/3) = -8

-2x -4 = -8

+4 +4

-2x = -4

x = 2

8 0

3 years ago