There are two possible answers to the question. I am choosing between 2 and 3.
2 and 3 can be the scale factors that produces and expansion under a dilation of the original image.
The original image is represented by 1. It is a dilation if the scale factor is more than 1. The value of the scale factor will increase if the dilated image is expanded.
<em>From the information given above, </em><u><em>D is the answer</em></u><em> which has a constant proportionality equal to 1. </em>
A scatter plot with a trend line that has a slope of 1/3 shows a positive correlation between the data. Positive correlation indicates that as one set of data increases, the other will also increase. A trend line shows a rough estimate on the relationship between two sets of data. A line with a slope of 1/3 is increasing, so this indicates that the data in the scatter plot are positively correlated.
Answer:
The box should have base 16ft by 16ft and height 8ft Therefore,dimensions are 16 ft by 16 ft by 8 ft
Step-by-step explanation:
We were given the volume of the tank as, 2048 cubic feet.
Form minimum weight, the surface area must be minimum.
Let the height be h and the lengths be x
the volume will be: V=x²h then substitute the value of volume, we have
2048=hx²
hence
h=2048/x²
Since the amount of material used is directly proportional to the surface area, then the material needs to be minimized by minimizing the surface area.
The surface area of the box described is
A=x²+4xh
Then substitute h into the Area equation we have
A= x² + 4x(2048/x²)
A= x² + 8192/x
We want to minimize
A
dA/dx = -8192/x² + 2 x= 0 for max or min
when dA/dx=0
dA/dx= 2x-8192/x²=0
2x=8192/x²
Hence
2x³=8192
x³=4096
x=₃√(4096)
X=16ft
Then h=2048/x²
h=2048/16²
h=8ft
The box should have base 16ft by 16ft and height 8ft
Hence the dimensions are 16 ft by 16 ft by 8 ft
Answer:
Step-by-step explanation:
The trick is not to include anything under and including 150 miles. So A B and C are not to be checked.
D and E are both true.
