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masya89 [10]
4 years ago
13

Find the x-intercept of the parabola with vertex (1,-17) and y-intercept (0,-16). type your answer in this form: (x1,y1), (x2,y2

). If necessary, round to the nearest hundredth.
Mathematics
1 answer:
vladimir1956 [14]4 years ago
3 0
Format for the equation of a parabola is : y = a(x - h)²<span> + k where (h, k) is the vertex. 

First, we plug in the value of the vertex, (1, -17) into the equation:
y = a(x - 1</span>)²<span> - 17

Next, we need to look for the value of a:
To find "a", we need to find a point on the graph. In this case, the graph has a y-intercept of (0,-16), we will use this point.
-16 = a (0 - 1</span>)²<span> - 17
-16 = a - 17
a = -16 + 17
a = 1

Now, we plug in the value of "a" into the equation and the equation is complete:
</span>y = (x - 1)² - 17

To find the x-intercept of the equation, we will plug in 0 for the value of y:
0 = ( x- 1)² - 17
(x - 1)² = 17
x- 1 = ±√17
x = √7 - 1 or -√7 -1
x = 1.65 or -3.65 (nearest hundredth)

Answer: The x-intercept are (1.65, 0) and (-3.65, 0)
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The equation of the line passing through the points (3, 16) and (5, 10) can be expressed as y = mx + b. Give the value of b
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we are given two points as

(3, 16) and (5, 10)

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slope is m

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m=\frac{y_2-y_1}{x_2-x_1}

now, we can plug points

m=\frac{10-16}{5-3}

m=\frac{-6}{2}

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we can plug it in y=mx+b

we get

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now, we can select any one points

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(3,16)

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16=-3*3+b

we can find b

b=25

now, we can plug back b

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y=-3x+25

so, equation is

y=-3x+25

and

b=25...............Answer

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