What is the equation of a circle with center (6,4) that passes through the coordinate (2,1)?
2 answers:
First find the radius of circle by finding the length from center to the given point well we need the square of radius r^2 = (6-2)^2 + (4-1)^2 = 25 equation of circle is (x - a)^2 + (y - b)^2 = r^2 where (a,b) is the center so our circle is (x - 6)^2 + ( y - 4)^2 = 25
The answer is going to be <span>(2,2) </span>
You might be interested in
-4+5n=18+3n=? so n=18+3n group like terms which would be
18+4n my beautiful queen
hope this helps
Since line c and d are parallel, line a can act as a transversal. Thus, x=124 degrees because of the alternate exterior angle relationship that can be seen.
Equilateral Isosceles Scalene Right Acute Obtuse
Answer:
$51.41
Step-by-step explanation:
trust
Answer:
4a=23
4a/4 = 23/4
a=5.75
Step-by-step explanation: