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lord [1]
3 years ago
13

What is the equation of a circle with center (6,4) that passes through the coordinate (2,1)?

Mathematics
2 answers:
Hoochie [10]3 years ago
8 0
First find the radius of circle by finding the length from center to the given point

well we  need the square of radius  r^2 = (6-2)^2 + (4-1)^2 = 25

equation of circle is (x - a)^2 + (y - b)^2 = r^2  where (a,b) is the center
so our circle is  
       (x - 6)^2 + ( y - 4)^2 = 25
gizmo_the_mogwai [7]3 years ago
7 0
The answer is going to be <span>(2,2) </span>
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3 years ago
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Please help<br> 1. f(x)=3(2)^x<br> 2. f(x)=2(3)^x<br> 3. f(x)=3(1/2)^x<br> 4. f(x)=2(1/3)^x
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