Their are 6 equilateral triangles in a regular hexagon:
The area of one triangle = (x²√3)/4, then:
1st answer: The area of the hexagon base: is 6 TIMES the area of one equilateral triangle [or, needed for 2nd, question, TOT AREA:(6x²√3)/4] = (3x²√3)/2] unit²
2nd answer: :
Volume of pyramid: (base area)(height)/3
Volume of pyramid: (3x²√3).(3x)/3 (because height = 3x, given)
Then Volume of pyramid= 3x³√3 unit³.
3 is the answer for the second question
and 6 for the 1st
Answer:
my putyy
Step-by-step explanation:
ong its my putty hehehe
Alright, lets get started.
We have given a circle which has 56 cm radius.
We are asked to find its circumference.
The formula for circumference of circle = 2 pi r
Putting the value of pi and r
So the circumference = 2 * 2.142 * 56
Simplifing
Hence the circumference of circle = 351.9 cms
Answer is 351.9 cm
Hope it will help :)
Answer:
No solution
Step-by-step explanation:
Step-by-step explanation:
8x + 14y = 4 ...1
-6x - 7y = -10 ...2
...2 × 2 in 2 sides of the equation
-12x -14y = -20 ...3
...1 + ...3
8x + 14y +(-12x -14y) = 4 +(-20)
8x + 14y - 12x -14y = 4 - 20
-4x = -16
x = (-16)/(-4)
= 4
replace x in ...1 or ...2 you will reserve y value
and answer in the term of (x,y)