(x + x² + 4x) 3
3(x) + 3(x²) + 3(4x)
3x + 3x² + 12x
Answer:
Step-by-step explanation:
304
Answer:
Given, two numbers 56 and 57 we need to find out the numbers lie between the squares of the given numbers.
Now, we have numbers lying between the square of n and (n + 1) is 2n
⇒ Numbers between squares of 56 and (56 + 1) = 2 × 56 = 112
Hence, 112 numbers lies between the square of the given numbers.
Answer:
Step-by-step explanation:
you just need to add both equations
you will get 3y=12+6=18
3y=18
y=6
now replace y=6
3x+12=6
3x=6-12
3x=-6
x=-2
(-2,6)
Answer:
Step-by-step explanation:
(14 + 7)/2 = 21/2= 10.5
(-2 + (-8))/2= -10/2= -5
Midpoint(10.5, -5)
