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nata0808 [166]
3 years ago
7

Jamie found the ISBN of the book she wanted to order in the Books in Print Catalog. To remember the eleven-digit number, 1977255

2901, she thought of the number as the year her best friend was born (1977) and her aunt's phone number (255-2901). Jamie was using the strategy of _____ to help her remember the ISBN number.
Computers and Technology
1 answer:
algol133 years ago
5 0

Answer:

Chunking

Explanation:

Chunking refers to the process of taking individual pieces of information (called chunks) and grouping them into larger units. By grouping each piece into a large whole, you can improve the amount of information you can remember.

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The concept of _________________ comes from the acknowledgment that data changes form and often gets copied, moved, and stored i
saveliy_v [14]

Answer: data loss protection

Explanation:

In any organization or enterprise it is very essential to provide protection from data loss to avoid breaches by unauthorized accesses and to secure the data irrespective of whether it is in rest or motion.

It is known that data changes its form when it is copied, moved and stored in different memory location so in this process a lot of sensitive data might be exposed to the outside world and left into the hands of the unauthorized for easy of access to it.

So once a security breach is possible through the system or into the network of the organization it would expose all the application database, emails, spreadsheets and the personal workstation files. So in such a scenario the importance of data loss protection is highlighted and must be given due importance.

8 0
3 years ago
Households pay taxes to the government and receive public services. Which of the following is a public service?
Gwar [14]
C. Roads  this is the correct answer
8 0
3 years ago
The function below takes a single parameter number_list which is a list that can contain integers and floats. Complete the funct
Andreas93 [3]

Answer:

  1. def getLargest(number_list):
  2.    new_list = []
  3.    for x in number_list:
  4.        if(isinstance(x, int)):
  5.            new_list.append(x)
  6.    largest = max(new_list)
  7.    return largest  

Explanation:

Firstly, create a function <em>getLargest()</em> that take one input parameter, <em>number_list</em>.

The function will filter out the float type number from the list by using <em>isinstance() </em>method (Line 5). This method will check if a current x value is an integer. If so, the x value will be added to <em>new_list</em>.

Next, use Python built-in <em>max</em> function to get the largest integer from the <em>new_list </em>and return it as output.

6 0
3 years ago
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katovenus [111]
White chicks is a good one
5 0
3 years ago
Read 2 more answers
Write a program that declares a two-dimensional array named myFancyArray of the type double. Initialize the array to the followi
kirill115 [55]

Answer:

This solution is provided in C++

#include <iostream>

using namespace std;

double sumFancyArray(double myarr[][6]){

   double sum = 0.0;

   for(int i = 0;i<2;i++)    {

       for(int j = 0;j<6;j++){

       sum+=myarr[i][j];    

       }}    

   return sum;

}

void printFancyArray(double myarr[][6]){

   for(int i = 0;i<2;i++)    {

       for(int j = 0;j<6;j++){

       cout<<myarr[i][j]<<" ";    

       }

   }

}

int main(){

   double myFancyArray[2][6] = {23, 14.12, 17,85.99, 6.06, 13, 1100, 0, 36.36, 90.09, 3.145, 5.4};

   cout<<sumFancyArray(myFancyArray)<<endl;

   printFancyArray(myFancyArray);

   

   return 0;

}

Explanation:

This function returns the sum of the array elements

double sumFancyArray(double myarr[][6]){

This initializes sum to 0

   double sum = 0.0;

This iterates through the row of the array

   for(int i = 0;i<2;i++)    {

This iterates through the column

       for(int j = 0;j<6;j++){

This adds each element

       sum+=myarr[i][j];    

       }}    

This returns the sum

   return sum;

}

This method prints array elements

void printFancyArray(double myarr[][6]){

This iterates through the row of the array

   for(int i = 0;i<2;i++)    {

This iterates through the column

       for(int j = 0;j<6;j++){

This prints each array element

       cout<<myarr[i][j]<<" ";    

       }

   }

}

The main starts here

int main(){

This declares and initializes the array

   double myFancyArray[2][6] = {23, 14.12, 17,85.99, 6.06, 13, 1100, 0, 36.36, 90.09, 3.145, 5.4};

This calls the function  that returns the sum

 cout<<sumFancyArray(myFancyArray)<<endl;

This calls the function that prints the array elements

   printFancyArray(myFancyArray);

   

   return 0;

}

Download cpp
7 0
3 years ago
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