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boyakko [2]
3 years ago
15

B3%7D%20%20%5Ctimes%20%20%5Cfrac%7B2%7D%7B3%7D%20%20" id="TexFormula1" title=" \frac{7}{3} \div \frac{2}{5} + \frac{4}{3} \times \frac{2}{3} " alt=" \frac{7}{3} \div \frac{2}{5} + \frac{4}{3} \times \frac{2}{3} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
telo118 [61]3 years ago
6 0
Your answer will be
\frac{140}{27}
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Again you don’t need to answer all of them but if you can do some that would be wonderful!
Maru [420]

Answer:

17)  x=7

18) x= -26

19) x= -8

20) x= 6

Step-by-step explanation:

17) is congruent

18) is supplementary

19) is congruent

20) is congruent

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3 years ago
Which expression can be used to find the area of a circle with a diameter of 80 cm?
ycow [4]
Its D............................
8 0
3 years ago
Please create an argument about a National Landmark/Monument. Do you think there is a monument/landmark out there that should no
Tanya [424]

Explanation:

The tallest national monument in America, it is a legendary engineering triumph, designed by Finnish-born architect Eero Saarinen. As part of the Jefferson National Expansion Memorial, the Gateway Arch serves to commemorate the accomplishments of 19th-century westward pioneers and celebrate the city’s role as the ‘Gateway to the West.’

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4 0
2 years ago
Suppose the total area is represented by the equation x^2+14x+24. If the area 1 is x^2 square units and area IV is 24 units, wha
Nutka1998 [239]

Answer:

See Explanation

Step-by-step explanation:

Given

Total = x^2 + 14x + 24

Area\ I = x^2

Area\ IV = 24

Required

True about area II and III

The question is incomplete; so, I will answer using general knowledge.

If the total area is:

Total = x^2 + 14x + 24

And there are 4 areas, then;

Total = Area\ I + Area\ II + Area\ III + Area\ IV

Rewrite as:

Total = Area\ I + Area\ IV+ Area\ II + Area\ III

This gives:

x^2 + 14x + 24 = x^2 + 24+ Area\ II + Area\ III

Collect like terms

x^2 -x^2 + 14x + 24 -24=  Area\ II + Area\ III

14x =  Area\ II + Area\ III

Rewrite as:

Area\ II + Area\ III  = 14x

<em>So, the sum of areas III and IV must be 14x</em>

4 0
3 years ago
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