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boyakko [2]
3 years ago
15

B3%7D%20%20%5Ctimes%20%20%5Cfrac%7B2%7D%7B3%7D%20%20" id="TexFormula1" title=" \frac{7}{3} \div \frac{2}{5} + \frac{4}{3} \times \frac{2}{3} " alt=" \frac{7}{3} \div \frac{2}{5} + \frac{4}{3} \times \frac{2}{3} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
telo118 [61]3 years ago
6 0
Your answer will be
\frac{140}{27}
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im just wondering if any of you guys have school bc todays election day and their a bunch of questions
bagirrra123 [75]

Answer:

i do have school today

Step-by-step explanation:

hope you have a good day though :)

3 0
2 years ago
Read 2 more answers
A fair coin will be tossed 3 times. What is the probability that one heads and two tails in any order will result?
ad-work [718]

Answer:

2

Step-by-step explanation:

If you toss a fair coin three times, these are the possible results.

HHH

HHT

HTH

HTT   <--------- one Heads, two Tails

THH

THT   <--------- one Heads, two Tails

TTH

TTT

Answer: 2

6 0
3 years ago
Convert the following decimals 1 / 8
Lostsunrise [7]

Answer:

. 125_________________

7 0
3 years ago
Read 2 more answers
An express train travels 80km/h from Ironton to Wildwood. A local train, traveling at 48km/h, takes 2 hours longer for the same
masha68 [24]

Answer:

They are 240 kilometers apart.

Step-by-step explanation:

This question can be solved using the following relation:

v = \frac{d}{t}

In which v is the velocity, d is the distance and t is the time.

An express train travels 80km/h from Ironton to Wildwood.

Here we have v = 80, t = x. So

v = \frac{d}{t}

80 = \frac{d}{x}

d = 80x

A local train, traveling at 48km/h, takes 2 hours longer for the same trip.

This means that when v = 48, t = x + 2[tex]. So[tex]v = \frac{d}{t}

48 = \frac{d}{x+2}

Since d = 80x

48 = \frac{80x}{x+2}

Applying cross multiplication

80x = 48(x + 2)

80x = 48x + 96

32x = 96

x = \frac{96}{32}

x = 3

So the distance is:

d = 80x = 80*3 = 240

They are 240 kilometers apart.

3 0
2 years ago
Is there any systematic tendency for part-time college faculty to hold their students to different standards than do full-time f
alexandr1967 [171]

Answer:

H0 : μ1 - μ2 = 0

H1 : μ1 - μ2 ≠ 0

-1. 34

0.1837

Step-by-step explanation:

Full time :

n1 = 125

x1 = 2.7386

s1 = 0.65342

Part time :

n2 = 88

x2 = 2.8439

s2 = 0.49241

H0 : μ1 - μ2 = 0

H1 : μ1 - μ2 ≠ 0

Test statistic :

The test statistic :

(x1 - x2) / sqrt[(s1²/n1 + s2²/n2)]

(2.7386 - 2.8439) / sqrt[(0.65342²/125 + 0.49241²/88)]

−0.1053 / sqrt(0.0034156615712 + 0.0027553)

-0.1053 /0.0785554

= - 1.34

Test statistic = - 1.34

The Pvalue :

Using df = smaller n - 1 = 88 - 1 = 87

Pvalue from test statistic score ;

Pvalue = 0.1837

Pvalue > α ; We fail to reject the null and conclude that the GPA does not differ.

At α = 0.01 ; the result is insignificant

6 0
2 years ago
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