Given:
Temperature in the morning = 6°F.
By the late afternoon, the temperature had dropped 9°F.
To find:
The temperature by the late afternoon.
Solution:
Temperature by the late afternoon = Morning temperature - Dropped temperature
Using the given values and the above formula, we get
Temperature by the late afternoon = 6°F - 9°F
Temperature by the late afternoon = -3°F
Therefore, the temperature by the late afternoon is -3°F.
Answer:
-37/6
Step-by-step explanation:
We are given two points: (-1, -1) and (1, -4). Slope is calculated as the change in y over the change in x, or rise over run.
The change in y is the difference of the two y coordinates (it doesn't matter the order): -1 - (-4) = 3
The change in x is the difference of the two x coordinates (this order depends on the order that you subtracted the y coordinates; they must be the same order): -1 - 1 = -2.
So, the slope is 3/-2
Answer:
so ......when you write the equation for this question,
the original height (H) = current height + the decreased height
i.e.
H= 347m + 182m
H = 529 m
so the original height of the helicopter is 529 meters
Step-by-step explanation:
21-3= 18 and 18 divided by 6 equals 3 so v=3
