Answer:
3: ![a^{2}+2ab+b^{2}](https://tex.z-dn.net/?f=a%5E%7B2%7D%2B2ab%2Bb%5E%7B2%7D)
4: ![8x^{3} -12x^{2}+6x-1](https://tex.z-dn.net/?f=8x%5E%7B3%7D%20-12x%5E%7B2%7D%2B6x-1)
Step-by-step explanation:
Question 3 can be re-written as:
![(a+b)(a+b)](https://tex.z-dn.net/?f=%28a%2Bb%29%28a%2Bb%29)
which equals:
![a^{2}+2ab+b^{2}](https://tex.z-dn.net/?f=a%5E%7B2%7D%2B2ab%2Bb%5E%7B2%7D)
Question 4 can be re-written as:
![(2x-1)(2x-1)(2x-1)](https://tex.z-dn.net/?f=%282x-1%29%282x-1%29%282x-1%29)
Doing the first 2 brackets gives us:
![(4x^{2} -4x+1)(2x-1)](https://tex.z-dn.net/?f=%284x%5E%7B2%7D%20-4x%2B1%29%282x-1%29)
Expanding these two:
![8x^{3} -4x^{2} -8x^{2} +4x+2x-1](https://tex.z-dn.net/?f=8x%5E%7B3%7D%20-4x%5E%7B2%7D%20-8x%5E%7B2%7D%20%2B4x%2B2x-1)
Simplifying it:
![8x^{3} -12x^{2}+6x-1](https://tex.z-dn.net/?f=8x%5E%7B3%7D%20-12x%5E%7B2%7D%2B6x-1)
Answer:
e.
Step-by-step explanation:
I hope i helped! ~ Best of Luck!~
Updated!
Answer:
The answer would be A
Step-by-step explanation:
consider the following image