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LekaFEV [45]
3 years ago
11

N(17+x)=34x−r Solve for x

Mathematics
1 answer:
romanna [79]3 years ago
7 0
N(17+x)=34x−r
17n+xn=34x-r
xn= 34x - r - 17n
xn-34x= -r - 17n
x(n-34)= -r - 17n
x= (-r - 17n)/(n-34)

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( _ + i ) + ( 4 _ ) = 10 - 7i
Margaret [11]
2 8 if not I’m so sorry pls forgive me
4 0
4 years ago
An exterior angle of a triangle is 140 degrees. If the non-adjacent angles are congruent, then what are the measures of all of t
trasher [3.6K]

The measures of all of the interior angles of the triangle are 70 degrees, 70 degrees and 40 degrees

<em><u>Solution:</u></em>

Given that exterior angle of triangle is 140 degrees

The exterior angle of a triangle is equal to the sum of the measures of the two non-adjacent interior angles

Given that adjacent angles are congruent

Let one of the non adjacent interior angles be "x"

x + x = 140

2x = 140

x = 70

So the two interior angles are 70 degrees and 70 degrees

Let us find the third interior angle

The angle sum property of a triangle states that the interior angles of a triangle always add up to 180 degrees

70 + 70 + third angle = 180

third angle = 180 - 70 - 70

third angle = 180 - 140

third angle = 40 degrees

Thus the measures of all of the interior angles of the triangle are 70 degrees, 70 degrees and 40 degrees

3 0
3 years ago
Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be
Oksana_A [137]
<h2>Hello!</h2>

The answers are:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

<h2>Why?</h2>

To calculate the speed of the cars, we need to write two equations, one for each car, in order to create a relation between the two speeds and be able to calculate one in function of the other.

So,

Tet be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

x_{FirstCar}=x_o+v*t

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

x_{SecondCar}=x_o+(v+14mph)*t

Now, from the statement that both cars met after 2 hours and 45 minutes, and the distance between to cover (between A and B) is 264 miles,  so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph

Then, since we know that they covered a combined distance equal to 264 miles in 2 hours + 45 minutes, we have:

2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours

Writing the equation:

264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph

So, the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph

We have that the speed of the second car is equal to 55 mph.

Hence, the answers are:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

Have a nice day!

7 0
3 years ago
Jimmy’s new cell phone cost him $49.99 when he signed a 2 year plan, which was 75% off the original place. What was the original
Sati [7]
If Jimmy's new cell cost him $49.99 with a 75% discount, then $49.99 is <span>100%−75%=25%</span><span> of the original price.
</span>
The original price of the cell phone was <span>$199.96</span><span>.</span>
6 0
4 years ago
Use the graph of the function to find, f(-6)
kati45 [8]

Answer:

f(-6) = 3

Step-by-step explanation:

In order to find the value of f(-6), we need to find what y-value appears associated with x = -6 according to the graph resented.

Therefore, go to x = -6 on the horizontal axis (six units to the left of the origin of the coordinate system), and find at what value of the y-axis the vertical grid passing through x = -6 intercepts the graph of the function.

That is indicated by a red dot in the attached image.

We see therefore that for x = -6 the y-value that the graph of the function shows in the vertical scale is "3".

Then, f(-6) = 3

5 0
3 years ago
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