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matrenka [14]
3 years ago
15

PLEASE SOMEONE HELP ME!!! I'm stuck on this problem!!! (THE DIRECTION IS ---"Find the area of the figure")

Mathematics
2 answers:
Juliette [100K]3 years ago
8 0
I think the answer is 5875, but you might have to simplify it i'm not sure
svetlana [45]3 years ago
5 0
A = 3,953 in²

You find the area of the whole triangle:
1/2bh = 1/2(63+31)(63+62) = 5875

Then subtract the missing rectangle:
lw = (62)(31) = 1922

5875 - 1922 = 3953 inches

Since you're multiplying inches by inches, it's inches².

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saveliy_v [14]

Answer:

$140

Step-by-step explanation:

1 meal --- $15

8 meals --- $15 × 8 = $120

Total = $120 + $20

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6 0
3 years ago
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When viewed from the front, the rope used to tie down a tent forms a pair of supplementary angles with the ground. Find m abc​
DedPeter [7]

Supplementary angles are angles that add up to 180 degrees.

180 = 3x + 4 + 8x + 11

Combine like terms.

180 = 11x + 15

Subtract 15 from both sides.

165 = 11x

Divide both sides by 11

15 = x

m<ABC = 3x + 4 = 3(15) + 4 = 45 + 4 = 49 degrees.

8 0
2 years ago
Removing which point from the coordinate plane would make the graph a function of x? mc006-1.jpg
Marianna [84]
B. (-2,1)

By checking the x coordinates, I saw there was two -2, but the output was different, so one of them had to be taken out to make it a function.

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5 0
2 years ago
Does y=2x-4 represent a linear function?
Tanya [424]

Answer:

Yes

Step-by-step explanation:

This equation is in slope-intercept form, y=mx+b. If graphed, it would be a line.

Hope this helps!

5 0
2 years ago
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Learning Task 3. Find the equation of the line. Do it in your notebook.
Wewaii [24]

Answer:

1) The equation of the line in slope-intercept form is y = 5\cdot x +9. The equation of the line in standard form is -5\cdot x + y = 9.

2) The equation of the line in slope-intercept form is y = \frac{2}{5}\cdot x +\frac{14}{5}. The equation of the line in standard form is -2\cdot x +5\cdot y = 14.

3) The equation of the line in slope-intercept form is y = 3\cdot x +4. The equation of the line in standard form is -3\cdot x +y = 4.

4) The equation of the line in slope-intercept form is y = 2\cdot x + 6. The equation of the line in standard form is -2\cdot x +y = 6.

5) The equation of the line in slope-intercept form is y = \frac{5}{6}\cdot x -\frac{7}{6}. The equation of the line in standard from is -5\cdot x + 6\cdot y = -7.

Step-by-step explanation:

1) We begin with the slope-intercept form and substitute all known values and calculate the y-intercept: (m = 5, x = -1, y = 4)

4 = (5)\cdot (-1)+b

4 = -5 +b

b = 9

The equation of the line in slope-intercept form is y = 5\cdot x +9.

Then, we obtain the standard form by algebraic handling:

-5\cdot x + y = 9

The equation of the line in standard form is -5\cdot x + y = 9.

2) We begin with a system of linear equations based on the slope-intercept form: (x_{1} = 3, y_{1} = 4, x_{2} = -2, y_{2} = 2)

3\cdot m + b = 4 (Eq. 1)

-2\cdot m + b = 2 (Eq. 2)

From (Eq. 1), we find that:

b = 4-3\cdot m

And by substituting on (Eq. 2), we conclude that slope of the equation of the line is:

-2\cdot m +4-3\cdot m = 2

-5\cdot m = -2

m = \frac{2}{5}

And from (Eq. 1) we find that the y-Intercept is:

b=4-3\cdot \left(\frac{2}{5} \right)

b = 4-\frac{6}{5}

b = \frac{14}{5}

The equation of the line in slope-intercept form is y = \frac{2}{5}\cdot x +\frac{14}{5}.

Then, we obtain the standard form by algebraic handling:

-\frac{2}{5}\cdot x +y = \frac{14}{5}

-2\cdot x +5\cdot y = 14

The equation of the line in standard form is -2\cdot x +5\cdot y = 14.

3) By using the slope-intercept form, we obtain the equation of the line by direct substitution: (m = 3, b = 4)

y = 3\cdot x +4

The equation of the line in slope-intercept form is y = 3\cdot x +4.

Then, we obtain the standard form by algebraic handling:

-3\cdot x +y = 4

The equation of the line in standard form is -3\cdot x +y = 4.

4) We begin with a system of linear equations based on the slope-intercept form: (x_{1} = -3, y_{1} = 0, x_{2} = 0, y_{2} = 6)

-3\cdot m + b = 0 (Eq. 3)

b = 6 (Eq. 4)

By applying (Eq. 4) on (Eq. 3), we find that the slope of the equation of the line is:

-3\cdot m+6 = 0

3\cdot m = 6

m = 2

The equation of the line in slope-intercept form is y = 2\cdot x + 6.

Then, we obtain the standard form by algebraic handling:

-2\cdot x +y = 6

The equation of the line in standard form is -2\cdot x +y = 6.

5) We begin with a system of linear equations based on the slope-intercept form: (x_{1} = -1, y_{1} = -2, x_{2} = 5, y_{2} = 3)

-m+b = -2 (Eq. 5)

5\cdot m +b = 3 (Eq. 6)

From (Eq. 5), we find that:

b = -2+m

And by substituting on (Eq. 6), we conclude that slope of the equation of the line is:

5\cdot m -2+m = 3

6\cdot m = 5

m = \frac{5}{6}

And from (Eq. 5) we find that the y-Intercept is:

b = -2+\frac{5}{6}

b = -\frac{7}{6}

The equation of the line in slope-intercept form is y = \frac{5}{6}\cdot x -\frac{7}{6}.

Then, we obtain the standard form by algebraic handling:

-\frac{5}{6}\cdot x +y =-\frac{7}{6}

-5\cdot x + 6\cdot y = -7

The equation of the line in standard from is -5\cdot x + 6\cdot y = -7.

6 0
2 years ago
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