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Rainbow [258]
2 years ago
8

What are the equivalent expressions ?

Mathematics
1 answer:
makvit [3.9K]2 years ago
6 0
2(x+3)=7(3x-2)
2x+6=21x-14
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If QR = 9 and ST = 13 calculate LM.
pickupchik [31]

Answer:

\boxed{\sf LM = 11}

Step-by-step explanation:

According to trapezoid mid-segment theorem:

LM = \frac{QR+ST}{2}\\ Given \ that\ QR = 9, ST = 13

\sf LM =  \frac{9+13}{2}

LM = 22/2

LM = 11

5 0
3 years ago
The area in the cylinder head where the air-and-fuel mixture is burned is called the
miv72 [106K]
   The area in the cylinder head where the air-and-fuel mixture is burned is called the combustion chamber. Hope this helps!
4 0
2 years ago
The amount of money spent on textbooks by a student during a semester at Norwich averages $340.00 with a standard deviation of $
dezoksy [38]

This question is incomplete

Complete Question

The amount of money spent on textbooks by a student during a semester at Norwich averages $340.00 with a standard deviation of $40.00. Find the probability that a randomly chosen student will spend a. less than $400 on textbooks in a semester b. between $400 and $460 on textbooks in a semester c. between $260 and $400 on textbooks in a semester

Answer:

a. 0.93319

b. 0.06546

c. 0.91044

Step-by-step explanation:

We solve using z score

z = (x-μ)/σ, where

x is the raw score

μ is the population mean = $340

σ is the population standard deviation = $40

a. less than $400 on textbooks in a semester

For x = $400

z = 400 - 340/40

z = 1.5

Probability value from Z-Table:

P(x<400) = 0.93319

b. between $400 and $460 on textbooks in a semester

For x = $400

z = 400 - 340/40

z = 1.5

Probability value from Z-Table:

P(x ≤ 400) = P(x = 400)

= 0.93319

For x = $460

z = 460 - 340/40

z = 3

Probability value from Z-Table:

P(x≤ 460) = (x = 460)

= 0.99865

The probability that a randomly chosen student will spend between $400 and $460 on textbooks in a semester is

P(x = $460) - P(x = $400)

= 0.99865 - 0.93319

= 0.06546

c. between $260 and $400 on textbooks in a semester

For x = $260

z = 260 - 340/40

z = -2

Probability value from Z-Table:

P(x≤ 260) = P(x = 260)

= 0.02275

For x = $400

z = 400 - 340/40

z = 1.5

Probability value from Z-Table:

P(x ≤ 400) = P(x = 400)

= 0.93319

The probability that a randomly chosen student will spend between $260and $400 on textbooks in a semester is

P(x = $400) - P(x = $260)

= 0.93319 - 0.02275

= 0.91044

4 0
3 years ago
5. Ruby's printer at home prints 25 photos in 12.5 minutes. Her work printer prints 12 photos in 3 minutes. Which printer is fas
victus00 [196]

Answer:

48 photos

Step-by-step explanation:

1 minute for home printer-> 25÷12.5=2

1 minute for work printer->12÷3=4

work printer is faster.

12 minutes for work printer->12×4=48

6 0
2 years ago
√x/√x+1 find Dervitive​
ivanzaharov [21]

d/dx √x/√(x + 1)

= d/dx √[x/(x + 1)]

= d/dx [x/(x + 1)]^(1/2)

= (1/2)[x/(x + 1)]^(- 1/2)

= (1/2)[x/(x + 1)]^(- 1/2) * (x + 1)^(-2)

Explanation:

√a/√b = √(a/b)

√x = x^(1/2)

Chain rule:

d/dx f(g(... w(x))) = f’(g(... w(x))) * g’(... w(x)) * ... * w’(x)

Quotient rule:

d/dx f(x)/g(x) = [f’(x)g(x) - g’(x)f(x)]/[g(x)]^2

8 0
3 years ago
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