Answer:
The first car is traveling at a speed of
s1=62 mi/hr.
The second car is traveling at a speed of s2=67 mi/hr.
Step-by-step explanation:
Let t be the amount of time the cars are traveling
s1=248/t and s2=268/t
We are told:
s1=s2-5
That is
248/t=268/t-5
⇒248=268- 5t
⇒5t=20
⇒t=4
s1=248/4=62
s2=268/4=67
Answer:

Step-by-step explanation:
-2x + 2y = -4 (times 3) -6x + 6y = -12
3x + 3y = -18 (times 2) 6x + 6y = -36
.
-6x + 6y = -12
<u>6x + 6y = -36 </u>+
12y = -48

y = -4
.
Substitute the value of y to the one of equations
-2x + 2(-4) = -4
-2x - 8 = -4
-2x = -4 + 8
-2x = 4

x = -2
Answer:
okay so do you have to answer in words? if so i can help
Step-by-step explanation:
I believe its 27 cause u have to multiply 3 times 3 which is 9, then 3 times 9 which is 27
Answer: wow
Step-by-step explanation: