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Charra [1.4K]
3 years ago
6

Select all the correct locations on the image. Select all the expressions that result in a product that is a rational number. MU

LITIPLE CHOICE
4/3 x 12/3

32/4 x 15/4

\sqrt{\frac{3}{2} } x 22/7

\sqrt{11} x 2/3
Mathematics
1 answer:
Allisa [31]3 years ago
4 0

Answer:

The 1st & 2nd option

Step-by-step explanation:

Ans1: 16/3

Ans2: 30

Ans3: 11/7×surd6

Ans4: 2/3×surd11

Rational number is a number that can be expressed in ratio (quotient)

It can be expressed in the form of repeating or terminating decimal

Example:

16/3 is equal to

5.3333333333....(repeating decimal)

thus it is a rational number

1/4 is equal to

0.25 (terminating decimal)

thus it is a rational number

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Given h(x)=4x-4h(x)=4x−4, find h(-3)h(−3).
jek_recluse [69]

Answer:1

Step-by-step explanation:

4x-4x+4=4h(x)

4=4h(x)

h(x)=1

h(-3)h(-3)=(1)(1)=1

3 0
3 years ago
1. Find 3 consecutive integers whose sum is 33.
statuscvo [17]

Answer: 10, 11, 12

Step-by-step explanation: Think of the integers like this:

1st integer: x

2nd integer: x+1

3rd integer: x+2

That is necessary because they are consecutive integers. Since the sum is 33, we need to create an equation.

x+x+1+x+2=33.

Simplify:

3x+3=33.

Opposite operations:

3x=-3+33.

To get the 3 close to the 33, we needed to make it negative, which is the opposite operation of the positive 3.

So,

3x=30.

Divide by 3:

x=10.

The first integer, x, equals 10.

To go with the guide that we already created,

1st integer: x=10

2nd integer: x+1=11

3rd integer:x+2=12.

Therefore, the three consecutive integers are 10, 11, and 12.

To check that, add them up. They all equal 33 and they are consecutive, which means this is the right answer!

5 0
4 years ago
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Archy [21]
You can literally get a calculator & use that but the answer is 0.00446323702
5 0
3 years ago
Solve for x. 1/2x - 1/4 = 1/2
sergey [27]

Answer:

x = 3/2

Step-by-step explanation:

Simplify this equation by dividing all three terms by 1/4:

2x - 1 = 2, or

2x  = 3

Then x = 3/2

6 0
3 years ago
Use the squared identities to simplify 2sin^2xsin^2x​
nataly862011 [7]

Answer:

option A  

Step-by-step explanation:

cos(4x) = cos(2x+2x) = cos(2x)*cos(2x) - sin(2x)*sin(2x)

cos(4x) = cos^2(2x) - sin^2(2x)

cos(4x) = cos^2(2x) - cos^2(2x) - 1     (using cos^2(2x) + sin^2(2x) = 1)

cos(4x) = 2cos^2(2x) - 1   (eq. 1)

cos(2x) = cos(x+x) = cos(x)*cos(x) - sin(x)*sin(x)

cos(2x) = cos^2(x) - sin^2(x)

cos(2x) = 1 - sin^2(x) - sin^2(x)     (using cos^2(x) + sin^2(x) = 1)

cos(2x) =  1 - 2sin^2(x)    (eq. 2)

Replacing eq. 2 into eq. 1:

cos(4x) = 2[1 - 2sin^2(x)]^2 - 1

cos(4x) = 2[1 - 4sin^2(x) + 4sin^4(x)] - 1

cos(4x) = 1 - 8sin^2(x) + 8sin^4(x)

cos(4x) - 1 + 8sin^2(x) = 8sin^4(x)

cos(4x)/4 - 1/4 + 2sin^2(x) = 2sin^4(x)

2sin^2(x)sin^2(x)​ = 2sin^4(x) = cos(4x)/4 - 1/4 + 2sin^2(x)

Using eq. 2:

2sin^2(x)sin^2(x)​ = cos(4x)/4 - 1/4 + 1 - cos(2x)

2sin^2(x)sin^2(x)​ = cos(4x)/4 + 3/4 - 4cos(2x)/4

2sin^2(x)sin^2(x)​ = [3 + cos(4x) - 4cos(2x)]/4

7 0
3 years ago
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