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satela [25.4K]
3 years ago
10

Answers to 2x-5=7 plz

Mathematics
2 answers:
Assoli18 [71]3 years ago
5 0

add 5 to -5 and 7.

That narrows it down to 2x =12

then you divide 2 to 2x and 12

Then its x = 6

so X = 6 !!!!!!

deff fn [24]3 years ago
3 0
2x-5=7
1. 2x-5+5=7+5
2. 2x=12
3. 2x÷2=12÷2
4. x=6
answer is x=6
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A test has 40 questions. Denise finished 2\5 of the questions in the first 10 minutes and 1\2 of the total questions in the next
leonid [27]

Answer:

28 questions answered.

Step-by-step explanation:

40(2/5) is 16 questions.

40-16 is 24 questions left.

24(.5) is 12 questions.

16+12 gets you 28 questions.

8 0
3 years ago
Joanna made a table and a graph for the equation y = 2x.
Leokris [45]
B. both r correct

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5 0
2 years ago
Read 2 more answers
If 5x+6-19=5 what is x
Troyanec [42]

Answer:

<em>x </em>equals 3.6.

Step-by-step explanation:

A way to solve this equation is to preform the inverse operations on both sides.

1. Add 19 to -19 and 5: 5<em>x </em>+ 6 - 19 + 19 = 5 + 19  ---> 5x + 6 = 24

2. Subtract 6 from 6 and 5: 5x + 6 - 6 = 24 - 6 ---> 5x = 18

3. Divide 5x and 18 by 5: 5x / 5 = 18 / 5 ---> x = 3.6

4. 3.6 is the answer.

To prove it, substitute x with 3.6 in the equation: 5 · 3.6 + 6 - 19 = 5

I hope this made sense and helped you a lot! :)

5 0
3 years ago
Read 2 more answers
What are the roots of the equation x^2+6x-9=10?
Ronch [10]

Answer:

-3+2sqrt7

-3-2sqrt7

Step-by-step explanation:

x^2+6x-9=10

x^2+6x-9-10=0

x^2+6x-19=0

ax^2+bx+c=0

a=1 b=6 c=-19

As cannot be solved by completing square we will use quadratic equation

x= (-b+sqrt(b^2-4ac))/2a     and      x= (-b-sqrt(b^2-4ac))/2a

x= (-6+sqrt(6^2-4*-19))/2     and      x= (-6-sqrt(6^2-4*-19))/2

x=(-6+sqrt(36+76))/2           and      x=(-6-sqrt(36+76))/2

x=(-6+4sqrt7)/2                   and       x=(-6-4sqrt7)/2

x=(-3+2sqrt7)                       and      x=(-3-2sqrt7)

x=2.29                                 and      x= -8.29

3 0
3 years ago
Find the values for a and b that would make the equality true.
Crank

Answer:

a = - 4, b = 5

Step-by-step explanation:

Expand the left side and compare the coefficients of like terms on the right side.

- 3(2x² + ax + b)

= - 6x² - 3ax - 3b

Comparing like terms with - 6x² + 12x - 15

x - term → - 3a = 12 ( divide both sides by - 3 )

                    a = - 4

constant term → - 3b = - 15 ( divide both sides by - 3 )

                               b = 5

6 0
3 years ago
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