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Evgen [1.6K]
3 years ago
5

Numbered disks are placed in a box and one disk is selected at random. If there are 6 red disks numbered 1 through 6, and 2 yell

ow disks numbered 7 through 8, find the probability of selecting a red disk, given that an odd-numbered disk is selected.
Mathematics
1 answer:
Tatiana [17]3 years ago
6 0

Answer:

\frac{3}{4}

Step-by-step explanation:

Total number of red disk=6

Total number  of yellow disk=2

Total disk=6+2=8

Odd number=1,3,5,7=4

Odd number on red disk=1,3,5=3

Probability,P(E)=\frac{favorable\;cases}{total\;number\;of\;cases}

Using the formula

The probability of getting odd number disk=\frac{4}{8}=\frac{1}{2}

The probability of getting odd numbered  red disk=\frac{3}{8}

The probability of selecting a red disk,given that an odd numbered disk is selected=\frac{\frac{3}{8}}{\frac{1}{2}}=\frac{3}{8}\times 2=\frac{3}{4}

Using conditional probability

P(A/B)=\frac{P(A\cap B)}{P(B)}

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