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777dan777 [17]
3 years ago
15

Question 3 Find the constant of variation (k). -y + 9x = 0

Mathematics
1 answer:
egoroff_w [7]3 years ago
3 0

Answer:

9

Step-by-step explanation:

-y + 9x = 0

y = 9x

y = kx

k = 9

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1) Erik has a job at Hobby Lobby and he
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Answer:

78

Step-by-step explanation:

is there more to this problem?

13. 00* 6 = 78

7 0
2 years ago
1<br> Enter the correct answer in the box.<br> Simplify the expression (62,4.
adelina 88 [10]

Answer:

248

Step-by-step explanation:

(62)4

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Suppose that a bored student wants to go to a restaurant for lunch, but she only has an hour in which to go, eat, and get back i
Blababa [14]

Missing information

Take local speed ad 30 mph and express your answer in miles

Answer:

7.5 miles

Step-by-step explanation:

Time for lunch is 1 hour but once will wait for 30 minutes before served and eat.

Out of 1 hour, 30 mins is for service and eating to mean time to get from work to restaurant, to and fro is the other 30 mins

Since 30 mins is for to and fro, then one way direction takes 15 mins.

Speed, s=d/t and distance d=speed*time

Given local speed of 30 mph and time as 15 mins,

To convert minutes to hours, we divide it by 60 hence the distance is

30*15/60=7.5 miles

Therefore, the student can go to a restaurant that is 7.5 miles from the office.

4 0
3 years ago
Someone help me please:)
Kryger [21]

Answer:

a. The time to strike the ground is 5 seconds

b. The time for the ball to be over than 96 ft is 1 second

Step-by-step explanation:

a. When the ball thrown vertically up ward to reach its maximum height at velocity = 0 then complete its motion vertically down ward to strike the ground its displacement = zero

∴ s(t) = 0 ⇒ 80t-16t^{2}=0

∴16t(5 - t) = 0

5 - t = 0⇒ ∴ t = 5 seconds

b. To tind the time that the ball will be over 96 ft over the ground substitute in s(t)=80t-16t^{2}

96=80t-16t^{2}

16t^{2}-80t+96=0

16(t^{2}-5t+6)=0

16(t-3)(t-2)=0

t = 3 sec. and t = 2 sec.

The ball will be at height 96 ft at time 2 sec. and 3 sec.

So the ball will be at height over than 96 = 3 - 2 = 1 sec.

8 0
3 years ago
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