What is the degree of 4a^5b^2+2ab^3 A) 5 B) 7 C) 10 D) 11

Andreas93 [3]

Because it is a rectangle, the area is expressed as A = xy, or length times width.

Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.

Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get:

Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get:

Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for x

Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equation

Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distribute

Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distributeA = -2y2 +7500y

Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distributeA = -2y2 +7500y

Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distributeA = -2y2 +7500y You can see that this is a parabola which opens down, meaning that the point of maximum area will be at the vertex, y = - b/2a = -7500/[2(-2)] = 1875

/2a = -7500/[2(-2)] = 1875 

/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750

/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750 

/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750 A = 3750(1875) = 7,031,250 m2

/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750 A = 3750(1875) = 7,031,250 m2 

5 0

2 years ago

210÷5 first u break it down and divide it step by step and it =42

Artyom0805 [142]

That is the correct answer

6 0

2 years ago

Consider the figure. Find AB if BC = 3, BD = 5, and AD = 5. AB= ?

blondinia [14]

Answer is 9.5 First find DC by doing the Pythagorean theorem
BC is 3 BD is 5
So 3^2+ DC= 5^2
9+____=25
So DC is 4 cuz 4times 4=16

Now add AD+DC=AC

5+4=9

So BC is 3 the bottom AC is 9
3^2+9^2= 9+81=90 the sq rt of 90 is 9.5

7 0

3 years ago

Read 2 more answers

A rancher has 800 feet of fencing to put around a rectangular field and then subdivide the field into 3 identical smaller rectan

Fittoniya [83]

Let x be the shorter side, and y be the longer side

There would be 4 fences along the shorter side, and 2 fences along the longer side

4x + 2y = 800

Rewrite in terms of y:

y = 400 − 2x

The area of the rectangular field is

A = x*y

Replace Y with the equation above:

A = x(400 − 2x)

A = − 2x^2 + 400x

The area is a parabola that opens downward, the maximum area would occur at the parabola vertex.

At the vertex

x = −b/2a

= −400/[2(−2)]

= 100

y = 400 −2x

y = 400 -2(100)

y = 400-200

y = 200

The dimension of the rectangular field that maximize the enclosed area is 100 ft x 200 ft.

8 0

3 years ago

i know what i entered are not the correct answers smh, someone please help w the correct answers!!! due today ;(

Oduvanchick [21]

Answer:

Ask your mom

Step-by-step explanation:

7 0

3 years ago