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dlinn [17]
2 years ago
9

3. In order to become a member of the library-all-star-members club, there is a $40 sign-up fee and a $2 monthly fee. Write an e

quation in slope-intercept form that models this situation. Answer:Y=2x+40 4. Use equation you wrote in problem 3 to find the total cost of being an all-star library member for 19 months.
Mathematics
2 answers:
eduard2 years ago
8 0

Answer:

$78

Step-by-step explanation:

In the equation y = 2x + 40, x represents the number of months the member is a part of the club.

We are given that a certain member is part of the club for 19 months, so we substitute the number 19 in for x:

y = 2x + 40 = 2 * 19 + 40 = 38 + 40 = 78.

Thus, the total cost is $78.

Hope this helps!

kirza4 [7]2 years ago
6 0

Answer:

$78

Step-by-step explanation:

Y = 2X + 40

X = 19

Y = 2(19) + 40

Y = 78

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Using the method described in part F, help Kevin change 9/2= x/24 to an equation without fractions. Show your work. Don't solve
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where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤
marusya05 [52]

THIS IS THE COMPLETE QUESTION BELOW

The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.

Answer

$168.27

Step by step Explanation

Given p=90000/400+3x

With the limits of 40 to 50

Then we need the integral in the form below to find the average price

1/(g-d)∫ⁿₐf(x)dx

Where n= 40 and a= 50, then if we substitute p and the limits then we integrate

1/(50-40)∫⁵⁰₄₀(90000/400+3x)

1/10∫⁵⁰₄₀(90000/400+3x)

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90000/(10)(3)∫3dx/(400+3x)

3000[ln400+3x]₄₀⁵⁰

Then let substitute the upper and lower limits we have

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3000[0.056]

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the average price p on the interval 40 ≤ x ≤ 50 is

=$168.27

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3 years ago
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