Answer:
Step-by-step explanation:
There is <em>one-and-a-half</em> <em>hour</em> in <em>ninety</em><em> </em><em>minutes</em>,<em> </em>so multiply 6 by 15 to get 90, then whatever is done to the bottom is also done to the top, so you <em>square</em> 6 to get 36.
I am joyous to assist you anytime.
Answer:
0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.
The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.
Step-by-step explanation:
Assume that the probability of a defective computer component is 0.02. Components are randomly selected. Find the probability that the first defect is caused by the seventh component tested.
First six not defective, each with 0.98 probability.
7th defective, with 0.02 probability. So
0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.
Find the expected number and variance of the number of components tested before a defective component is found.
Inverse binomial distribution, with
Expected number before 1 defective(n = 1). So
Variance is:
The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.
Answers:
P(A) = 7/12
P(B) = 1/4
====================================================
Explanation:
Instead of having one die, let's say we have two dice. I'll make one red and the other blue.
I'll be using the dice chart shown below. The red and blue values add up to the black numbers inside the table. For instance, we have 1+1 = 2 in the upper left corner. There are 6*6 = 36 sums total.
Using that table, we can see the following:
In total, we have 6+5+4+3+2+1 = 21 instances where the two dice add to something larger than 6.
This is out of 36 ways to roll two dice.
Therefore P(A) = 21/36 = (3*7)/(3*12) = 7/12
-----------------------------------
If a number is divisible by 4, then it is a multiple of 4.
The multiples of 4 found in the table are: 4, 8, 12
We have
This gives 1+5+3 = 9 values that are a multiple of 4
P(B) = 9/36 = (1*9)/(4*9) = 1/4
Given:
The faces on a number cube are labeled 1,2,2,3,4, and 5.
The number cube is rolled 114 times.
To find:
How many times would you expect the number 2 to appear?
Solution:
We have,
Total outcomes = 1,2,2,3,4, and 5.
Number of total outcomes = 6
Favorable outcomes = 2 and 2
Number of favorable outcomes = 2
The probability of getting 2 is:
Now, the expected number of times when 2 to appear is:
Therefore, the expected number of times is 38.