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3 years ago

Determine if each statment illustrates the distributive property.Select Yes or No.

Mathematics

2 answers:

Paha777 [63]3 years ago

4 0

A.)No
b.)Yes
c.)Yes
d.)No

Hope this helped :)

Ray Of Light [21]3 years ago

3 0

No besides b pls give me the brainlyist anser if im right

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HELP NEEDED! 15 POINTS!<br> Given that m

S_A_V [24]

Answer:

140°

Step-by-step explanation:

arc ER = 2×70° = 140°

7 0

3 years ago

Use the point-slope formula to write an equation of the line that passes through (6,23) and has a slope of m= 3. Write the answe

RSB [31]

y=3x+5

plug your coordinate points into the equation for slope (left corner or the paper)

multiply by the denominator on both sides of the equation

x-6 cancels out and leaves y-23=3(x-6)

multiply x and -6 by 3

add 23 to both sides to isolate y

hope this helps!

4 0

3 years ago

If f(x)=square root 4x+9+2, which inequality can be used to find the domain of f(x)?

jenyasd209 [6]

we have

$f(x)=\sqrt{4x+9} +2$

we know that

The radicand must be greater than or equal to zero

$4x+9 \geq0 \\ 4x\geq -9 \\x\geq -\frac{9}{4} \\ x\geq -2.25$

the domain is is the interval--------> [-2.25,∞)

therefore

<u>the answer is</u>

$4x+9 \geq0$

8 0

3 years ago

Read 2 more answers

What is 24.2% of 120

katen-ka-za [31]

Answer:

29.04

Step-by-step explanation:

Multiply: 120*.242=29.04

It's multiplied by .242 bc if you want to turn a percentage into a decimal you need to move the decimal twice to the left. So, 24.2 becomes .242.

3 0

3 years ago

A process is normally distributed with a mean of 104 rotations per minute and a standard deviation of 8.2 rotations per minute.

Ilia_Sergeevich [38]

Answer:

Option B) In control as this one data point is not more than three standard deviations from the mean

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 104 rotations per minute

Standard Deviation, σ = 8.2 rotations per

We are given that the distribution of process is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

For x = 118

$z = \displaystyle\frac{118-104}{8.2} = 1.7073$

Thus, we could say that this data point lies within three standard deviations from the mean as:

$\mu - 3\sigma < x < \mu + 3\sigma\\104-3(8.2) < x < 104 + 3(8.2)\\79.4 < 118 < 128.6$

Thus, it could be said

Option B) In control as this one data point is not more than three standard deviations from the mean

6 0

4 years ago