Answer:
500
105
Step-by-step explanation:
This question would be solved using a simultaneous equation
let
a = number of adults who bought the ticket
b = number of students who bought the ticket
c = number of senior citizens who bought the ticket
a + b + c = 670 eqn 1
10a + 4b + 3c = 5615 -- eqn 2
If 65 senior citizen bought the ticket, substitute for c in equation 1 and 2
a + b + 65 = 670
a + b = 670 - 65
a + b = 605 eqn 3
10a + 4b + 3(65) = 5615
10a +4b = 5420 eqn 4
multiply equation 3 by 10 to derive equation 5. Subtract eqn 4 from eqn 5
10a + 10b = 6050 eqn 5
-
10a + 4b = 5420 eqn 4
= 6b = 630
b = 105
Students who bought the ticket are 105
Substitute for b in eqn 3
a + 105 = 605
a = 500
Adults who bought the ticket are 500
Answer: 1/12
Step-by-step explanation: 1/2 / 6 = 1/2 X 1/6 = 1/12
To get this equation you have to perform KCF which stands for Keep Change Flip. KCF is only to be used for division fraction problems. KCF means you Keep the first Fraction, then change the division sign into a multiplication sign. and last flip the last fraction.
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HOPE THIS HELPED!!</h2>
B because it’s rotating in a circle
Tens = 7030 hundreds =7000
Answer: 90,75. cos 55°. sin55° ≈ 42,64
through E, draw EK perpendicular to BC (F ∈ BC)
because E is the midpoint of AB => BE = 11/2 = 5.5
ΔBEF is a right triangle at K
=> sin 55° = EK/BE
=> EK = 5,5.sin 55°
ΔABC has E and F is the midpoints of AB and AC
=> EF is the median line of the triangle
=> EF = 1/2.BC
through A, draw AD perpendicular to BC
=> ΔABD is a right triangle at D
=> BC = 11.cos 55°.2 = 22.cos 55°
=> EF = 11.cos 55°
=>the area of the trapezium BEFC is:
Step-by-step explanation:
