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-BARSIC- [3]
3 years ago
7

G. Write the equation of the line in slope-intercept form.

Mathematics
1 answer:
Neko [114]3 years ago
6 0

Answer:

  • y= x-2
  • y = 4/5 x+39/5

Step-by-step explanation:

1.

(3,1) and\:perpendicular \:to \: y = -x+1\\(3,1) = (x,y)\\m = -1\\In\: perpendicularism ; m_2 = \frac{-1}{m_1} \\m_2 = \frac{-1}{-1} \\m_2 =1\\y = mx+c\\1 = 1(3) +c\\1=3+c\\1-3=c\\-2 =c\\Substitute \:new \:values\:into\\y =mx+c\\y = 1x -2\\y = x-2

2.

(-1,7) =(x_1,y_1)\\\\5y = 4x+5\\\\Write\:in\:y=mx+c\:form\\\frac{5y}{5} = \frac{4}{5} x + \frac{5}{5} \\y = \frac{4}{5} x +1\\m = \frac{4}{5} \\\\y -y_1=m(x-x_1)\\y-7=\frac{4}{5} (x -(-1)\\y -7 = 4/5(x+1)\\y -7 = 4/5x +4/5\\\\y = \frac{4}{5} x+\frac{4}{5} +7\\\\y = \frac{4}{5} x +39/5

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Answer:

a) (1215, 1297)

b) (1174,  1338)

c) (1133, 1379)      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1256

Standard Deviation, σ = 41

Empirical Rule:

  • Also known as 68-95-99.7 rule.
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  • About 68% of data lies within 1 standard deviation of mean.
  • About 95% of data lies within two standard deviation of mean.
  • About 99.7% of data lies within 3 standard deviation of mean.

a) range of years centered about the mean in which about 68% of the data lies

\mu \pm 1(\sigma)\\=1256 \pm 41\\=(1215, 1297)

68% of data will be found between 1215 years and 1297 years.

b) range of years centered about the mean in which about 95% of the data lies

\mu \pm 2(\sigma)\\=1256 \pm 2(41)\\=1256 \pm 82\\=(1174, 1338)

95% of data will be found between 1174 years and 1338 years.

c) range of years centered about the mean in which about all of the data lies

\mu \pm 3(\sigma)\\=1256 \pm 3(41)\\=1256 \pm 123\\=(1133, 1379)

All of data will be found between 1133 years and 1379 years.

3 0
4 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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