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kherson [118]
3 years ago
7

What is the x-intercept of the graph 4x-6y=12

Mathematics
1 answer:
kap26 [50]3 years ago
4 0

Answer

x=3 or (3,0) and if you need it y=-2x+3

Step-by-step explanation:

I'm not very good at explaining things, sorry

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Match the graph with the correct equation
devlian [24]
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6 0
3 years ago
Please help with this thank you!
Umnica [9.8K]

Answer:

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5 0
3 years ago
5-2(4a+1)+3a=13 <br><br> A= 2/3<br> A= -2<br> A= -6/5<br> A=2
VMariaS [17]

Answer:

                   a = -2

Simplifying 5 + -2(4a + 1) + 3a = 13 Reorder the terms: 5 + -2(1 + 4a) + 3a = 13 5 + (1 * -2 + 4a * -2) + 3a = 13 5 + (-2 + -8a) + 3a = 13 Combine like terms: 5 + -2 = 3 3 + -8a + 3a = 13 Combine like terms: -8a + 3a = -5a 3 + -5a = 13 Solving 3 + -5a = 13 Solving for variable 'a'. Move all terms containing a to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -5a = 13 + -3 Combine like terms: 3 + -3 = 0 0 + -5a = 13 + -3 -5a = 13 + -3 Combine like terms: 13 + -3 = 10 -5a = 10 Divide each side by '-5'. a = -2

6 0
3 years ago
Can you answer the question for me? And no buggin cause I da need help
poizon [28]
<SUT is a right angle. 

I believe <SUW is equal to 152 degrees.
7 0
3 years ago
Autum school holding a voleturing challeng. Students are encouraged to volunteer for at least 1 1/2 hours per week. Volenteers a
Pani-rosa [81]

Given :

Challenge given is to volunteer for about 1 1/2 hours per week .

Autum did at a rate of 6 3/4 hours per week .

To Find :

The comparison ( ratio )  her volunteers rate with the challenge rate .

Solution :

Simplifying challenge rate in in normal fraction , 1\dfrac{1}{2}=\dfrac{2+1}{2}=\dfrac{3}{2} .

Also , simplifying her rate , 6\dfrac{3}{4}=\dfrac{(6\times 4)+3}{4}=\dfrac{27}{4} .

Now , ratio of his work by challenge is :

R=\dfrac{\dfrac{27}{4}}{\dfrac{3}{2}}\\\\\\R=\dfrac{27\times 2}{4\times 3}\\\\R=\dfrac{9}{2}

Therefore , the ratio is 9/2 or 4 1/2 .

Hence , this is the required solution .

8 0
3 years ago
Read 2 more answers
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