<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).
</span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).
</span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.
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<span>I hope this helps! </span>
Answer:
san po jan
<h3>step_by istep explanation_</h3>
Answer:
a) $86.11
b) $467.33
Step-by-step explanation:
no. of gallons saved 'n' per year
n = (10000/33) - (10000/36)
n = 2500/99
Amount saved = 3.41×n = 3.41×2500/99
= $86.11
b) over 5 years:
86.11( 1 + (1.041) + (1.041)² + (1.041)³ + (1.041)⁴ )
= 86.11(5.427157431)
= $467.33
Answer:
It's the first option: -5, 1 and 4
The symmetry line is passing through points F and E. Then the correct option is B.
<h3>What is reflectional symmetry?</h3>
Consider a plane. Consider a design or shape on that plane. Now consider an axis.
If we think of that axis as a mirror, and on the opposite side of that axis create the image of the considered shape, then if the shape's image looks exactly like the shape itself, then that shape is called to have reflectional symmetry.
Then the symmetry line is passing through points F and E. Because F and E are the mid-points of AD and BC.
Learn more about symmetry here:
brainly.com/question/7783612
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