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3 years ago

12

Need help an plz show me how you know so you can give me the work

1 answer:

lisov135 [29]3 years ago

8 0

You subtract the known angle measurements from 180 because a straight line means the whole undivided angle is 180 degrees and the answer to the subtraction is your missing angle measurement
I hope this helps!!!

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10-^4 in standard form

Harrizon [31]

Question: 10^-4 in standard form

Work:

To write 10^-4 in standard form you just simplify the equation.

10^-4 equals 1/10000 or 0.0001

Final Answer:

10^-4 equals 1/10000 or 0.0001

6 0

2 years ago

(show your work!) i only got an hour left for this :c

MA_775_DIABLO [31]

Answer:

7 _> x

Step-by-step explanation:

28 - x _> 7(x-4)

28 - x _> 7x-28

28+28 _> 7x+x

56 _> 8x

7 _> x

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3 years ago

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Jen’s goal is to run a total of 22 miles in five days. The table below shows her log for the number of miles she ran on Monday,

Ronch [10]

Answer: 5.875 miles run on Friday to reach her goal by Jen

Step-by-step explanation:

Since we have given that

Part of distance covered on Monday by Jen is given by

$4\frac{3}{4}=\frac{19}{4}$

Part of distance covered on Tuesday by Jen is given by

$5\frac{1}{8}\\\\=\frac{41}{8}$

Part of distance covered on Wednesday by Jen is given by

0

Part of distance covered on Thursday by Jen is given by

$6\frac{1}{4}\\\\=\frac{25}{4}$

Total part of distance covered in these four days by Jen is given by

$\frac{19}{4}+\frac{41}{8}+0+\frac{25}{4}\\\\=\frac{38+41+0+50}{8}\\\\=\frac{129}{8}=16.125\ miles$

Remaining part of distance will be covered on Friday to reach her goal which is given by

$22-16.125=5.875\ miles$

Hence, 5.875 miles run on Friday to reach her goal by Jen.

5 0

3 years ago

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Adult men have heights that a normally distributed with a mean of 69.5 inches and a standard deviation of 2.4 inches. Adult wome

Aliun [14]

Answer:

Step-by-step explanation:

From the information given:

For Adult Men

Mean $\mu$ = 69.5

Standard deviation $\sigma$ = 2.4

observed value X = 74

For Adult Women

Mean $\mu$ = 63.8

Standard deviation $\sigma$ = 2.6

observed value X = 70

Therefore ; the values for their z scores can be obtained in order to determine who is more unusually tall within his or her respective sex

For Adult Men :

$z = \dfrac{X- \mu}{\sigma}$

$z = \dfrac{74- 69.5}{2.4}$

$z = \dfrac{4.5}{2.4}$

z = 1.875

For Adult Women :

$z = \dfrac{X- \mu}{\sigma}$

$z = \dfrac{70- 63.8}{2.6}$

$z = \dfrac{6.2}{2.6}$

z = 2.3846

Thus; we can conclude that , the women is more unusually tall within his or her respective sex

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3 years ago

Need help with 9-12 plzzzzz

Vladimir79 [104]

Hi Lexia it's Aliyah

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3 years ago

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