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olya-2409 [2.1K]
4 years ago
12

Remmi wrote the equation of the line y=1/3(x+2) He solved for x and got x=3y-2 Which of the following is an equivalent equation

for x?
Mathematics
2 answers:
Oksanka [162]4 years ago
8 0

Just took the quiz.

The answer is x=3(y-2/3)

gregori [183]4 years ago
5 0
<span>the equation of the line y = 1/3 (x+2)
to solve for x , multiply the whole eqaution by 3, which results to:
</span>[y = 1/3 (x + 2)] 3
3y = x + 2
then transpose the 2 to the other side of the equation
3y - 2 = x
x = 3y - 2
so the answer of remmi is correct. i hope this can help you, feel free to ask for clarifications
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A ski resort gets an average of 2,000 customers per weekday with a standard deviation of 800 customers. Assume the underlying di
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Answer:

0.62% probability that a ski resort averages more than 3,000 customers per weekday over the course of four weekdays

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 2000, \sigma = 800, n = 4, s = \frac{800}{\sqrt{4}} = 400

Trobability a ski resort averages more than 3,000 customers per weekday over the course of four weekdays.

This is 1 subtracted by the pvalue of Z when X = 3000. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{3000 - 2000}{400}

Z = 2.5

Z = 2.5 has a pvalue of 0.9938

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0.62% probability that a ski resort averages more than 3,000 customers per weekday over the course of four weekdays

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Zscore = (11.5 - 16.7) / 3.8

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P(Z ≤ - 1.3684) = 0.085593 (Z probability calculator)

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Step-by-step explanation:

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