First, we can neglect the Ka2 value and use Ka1:
according to this equation and by using the ICE table:
H2Se ⇄ H+ +HSe-
initial 0.4 M 0 0
change -X +X +X
Equ (0.4-X) X X
so,
Ka1 = [H+][HSe-] / [H2Se]
so by substitution:
1.3 x 10^-4 = X*X / (0.4 -X) by solving for X
∴X = 0.00715
∴[H+] = 0.00715 m
∴PH = -㏒[H+]
= -㏒ 0.00715
= 2.15
It pulls you towards the ground therefore when we jump, or if you drop soemthing, it goes straight back down
Answer:
I believe your answer is : <u>The dog flu virus interacts specifically with receptors on the surface of dog cells.</u>
Explanation:
I hope this helps you :)
Pls mark brainleist :P
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<em>Tori </em>
Atomic mass of Br = 79.904
<span>Now lets say y% is abundance of 79Br. </span>
<span>Then abundance of 81Br = (100 - y) </span>
<span>mass due to 79Br = 78.9183 * y/100 = 0.789183y
</span><span>mass due to 81Br = 80.9163 x (100 - y)/100 = 0.809163(100 - y) </span>
<span>Therfore</span>
<span>0.789183y+ 0.809163(100 - y) = 79.904 </span>
<span>0.789183y + 80.9163 - 0.809163y = 79.904 </span>
<span> - 0.01998y= 79.904 - 80.9163
= - 1.0123 </span>
<span>y = 1.0123/0.01998 = 50.67% </span>
<span> 79Br = 50.67% </span>
<span>now
81Br = 100 - 50.67 = 49.33%
hope this helps</span>
