Answer:
T₂ = 721 k
Explanation:
Given data:
Initial volume = 285 mL
Initial pressure = 1.88 atm
Initial temperature = 355 K
Final temperature = ?
Final volume = 435 mL
Final pressure = 2.50 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
P₁V₁/T₁ = P₂V₂/T₂
T₂ = P₂V₂ T₁ / P₁V₁
T₂ = 2.50 atm × 435 mL × 355 K / 1.88 atm × 285 mL
T₂ = 386062.5 atm. mL. K /535.8 atm. mL
T₂ = 721 k
Chlorophyll, it is chlorophyll
Answer: 6
Explanation:
To find pH you have to do -log(concentration of H+)
Answer:
Boiling point of solution is 
Explanation:
Cane sugar is a non-volatile solute.
According to Raoult's law for a non-volatile solute dissolved in a solution-
Where, 
is elivation in boiling point of solution, 
is ebbulioscopic constant of solvent (how much temperature is raised for dissolution of 1 mol of non-volatile solute) and m is molality of solution.
Here, 
610 g of cane sugar = 
moles of cane sugar
= 1.78 moles of cane sugar
So, molality of solution (m) = 
Plug in all the values in the above equation, we get-
So, boiling point of solution = 
