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Andrej [43]
3 years ago
13

Graph y = −x^2 − 1. Identify the vertex of the graph. Tell whether it is a minimum or maximum.

Mathematics
1 answer:
bonufazy [111]3 years ago
5 0

Answer:

Step-by-step explanation:

since this is an upside down parabola shifted down 1 unit, the vertex must be at the point (0,-1).  It must be a <em>MAX</em> because the parabola is upside down

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Write the recursive rule and an explicit rule for the geometric sequence 9,27,81,243
SashulF [63]

Answer:

Recursive

a(1) = 9 ; a(n+1) = 3 * a(n)

Explicit

a(n) = 9 * 3^(n-1)


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3 years ago
Why is it important to use a device like a random number table in a simulation?
Jet001 [13]
I don’t think it’s the second or third one I’m narrowing it down to the first or maybe fourth

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3 years ago
29 If the zeros of a quadratic function, F, are -3 and 5, what is the equation of the axis of symmetry
UNO [17]

Answer:

the axis of symmetry is X = 1

Step-by-step explanation:

make sure to ask if you need any further guidance.

8 0
1 year ago
Find the domain of the function.<br><br><br><br> f(x) = -5x + 3
Sedaia [141]

Enter a problem...

Calculus Examples

Popular Problems Calculus Find the Domain and Range f(x)=5x-3

f

(

x

)

=

5

x

−

3

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Interval Notation:

(

−

∞

,

∞

)

Set-Builder Notation:

{

x

|

x

∈

R

}

The range is the set of all valid

y

values. Use the graph to find the range.

Interval Notation:

(

−

∞

,

∞

)

Set-Builder Notation:

{

y

|

y

∈

R

}

Determine the domain and range.

Domain:

(

−

∞

,

∞

)

,

{

x

|

x

∈

R

}

Range:

(

−

∞

,

∞

)

,

{

y

|

y

∈

R

}

3 0
2 years ago
Please help, i need to raise my grade
Dmitrij [34]

Answer:

r=\dfrac{v^2}{a}

Step-by-step explanation:

To isolate r, we're going to need to do some algebraic manipulation.

a=\dfrac{v^2}{r}

Multiply both sides by r:

a\cdot r=v^2

Divide both sides by a:

r=\dfrac{v^2}{a}

Hope this helps!

5 0
3 years ago
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