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FrozenT [24]
3 years ago
9

The table below shows data from a survey about the amount of time students spend doing homework each week. The students were eit

her in college or in high school:
High Low Q1 Q3 IQR Median Mean σ
College 50 5 7.5 15 7.5 11 13.8 6.4
HS 16 0 9.5 14.5 5 13 . 10.7 5.3
Which of the choices below best describes how to measure the spread of this data? (Hint: Use the minimum and maximum values to check for outliers.) (2 points) A:Both spreads are best described with the IQR.
B:Both spreads are best described with the standard deviation.
C:The college spread is best described by the IQR. The high school spread is best described by the standard deviation.
D:The college spread is best described by the standard deviation. The high school spread is best described by the IQR.
Mathematics
1 answer:
Nadusha1986 [10]3 years ago
4 0

Answer:

Option A is correct

Step-by-step explanation:

Given is a table which shows data from a survey about the amount of time students spend doing homework each week.

          College    HS

High    50            16

Low     5                0

Q1       7.5             9.5

Q3      15              14.5

 IQR    7.5             5

Median  11             13

Mean     13.8         10.7

Std dev 6.4            5.3

1.5IQR         11.25         7.5

Q1-1.5IQR     -9.38      -12

Q3+1.5IQR    37.5       29.5

WE find that there is only one outlier in college with 50 as high.

Except that all others are well within IQR range.  Hence outliers are minimum

So option A is right.

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Answer:

8

Step-by-step explanation:

because yes.

5 0
3 years ago
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Wha bout dis one????/
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6-3=3, so m=3. Easy as pie
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2 years ago
A fighter tank targets an enemy helicopter flying at an altitude of 1250 ft. If the ground
madam [21]

By using trigonometric relations, we will see that the angle of elevation must be 55°.

<h3>How to find the angle of elevation?</h3>

We can see this as a right triangle, where one cathetus measures 1250ft (altitude) and the other cathetus measures 875ft.

The angle of elevation is the angle such that the adjacent cathetus is the one measuring 875ft.

Then we can use the relation:

tan(a) = (opposite cathetus)/(adjacent cathetus)

tan(a) = 1250ft/875ft

To find the angle of elevation, we can use the inverse tangent function:

a = Atan(1250ft/875ft) = 55°

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7 0
1 year ago
Please help me label each triangle based on its angles and sides.
Olenka [21]

Answer:

90% of people marry there 7th grade love. since u have read this, u will be told good news tonight. if u don't pass this on nine comments your worst week starts now this isn't fake. apparently if u copy and paste this on ten comments in the next ten minutes you will have the best day of your life tomorrow. you will either get kissed or asked out in the next 53 minutes someone will say i love you(i got this from someone else)

Step-by-step explanation:

90% of people marry there 7th grade love. since u have read this, u will be told good news tonight. if u don't pass this on nine comments your worst week starts now this isn't fake. apparently if u copy and paste this on ten comments in the next ten minutes you will have the best day of your life tomorrow. you will either get kissed or asked out in the next 53 minutes someone will say i love you(i got this from someone else)

5 0
3 years ago
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What is the range of possible
olya-2409 [2.1K]

Answer:

4<C <10

Step-by-step explanation:

Theorem: Given a triangle with sides A, B and C the sum of the lengths of any two sides of a triangle must be greater than the third side:

1.  A+B>C

2.  B +C >A

3.  A+C>B

Thus given two sides of A=3 and B=7 C can be:

7 −3<C < 7+3

C range  

4<C <10

8 0
3 years ago
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