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Given are three married couples.
So, let us assume there are 3 men and 3 women
They are sitting in a row of 6 empty seats
There is a definite order constraint that each woman will sit left to her husband. The first woman gets 3 options to choose from 3 available seats. The second woman has two options left as already one seat is filled by the first woman. The last woman has one option left. So, it is
So, number of ways is 3! = = 6 ways.
Answer: There are 1800 unique names from both the lists.
Explanation:
Since we have given that
there are two lists :
In First list, number of names = 1200
In Second list, number of names = 900
According to question , we have also given that
there are 150 names that appear on both lists,
So,
Number of unique names in the first list is given by
Number of unique names in the second list is given by
Therefore, total number of unique names is given by
Hence, there are 1800 unique names from both the lists.