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arsen [322]
3 years ago
14

Person to get this question right will get brainliest: If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 li

ters, what is the temperature?
Mathematics
2 answers:
dybincka [34]3 years ago
5 0

Answer:

If i have three moles of a gas at a pressure of 5.6 atm and a volume of 3 liters, what is the temperature ?

We have the following data:

n (number of moles) = 3 moles

P (pressure) = 5.6 atm

V (volume) = 12 L

T (temperature) = ? (in Kelvin)

R (gas constant) = 0.082 atm.L / mol.K

We apply the data above to the Clapeyron equation (gas equation), let's see:

Answer:

The temperature is approximately 205 Kelvin

inysia [295]3 years ago
4 0

Answer:

Okay so according to the formula PV=nRT

n=4

P=5.6 atm

V=12 L

R=0.08206 L atm mol-1 K-1

T=?

So, if you plug it in, you will get:-

T=PV/nR

T=(5.6 atm)(12 L)/(4 mol)(0.08206 L atm mol-1 K-1)

T=204.73 K

Hope I'm right! :)

Step-by-step explanation:

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The matrix A= (−3 0 1, 2 −4 2, −3 −2 1) has one real eigenvalue. Find this eigenvalue, its multiplicity, and the dimension of th
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Answer:

a) -4

b) 1

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Step-by-step explanation:

a) The matrix A is given by:

A=\left[\begin{array}{ccc}-3&0&1\\2&-4&2\\-3&-2&1\end{array}\right]

to find the eigenvalues of the matrix you use the following:

det(A-\lambda I)=0

where lambda are the eigenvalues and I is the identity matrix. By replacing you obtain:

A-\lambda I=\left[\begin{array}{ccc}-3-\lambda&0&1\\2&-4-\lambda&2\\-3&-2&1-\lambda\end{array}\right]

and by taking the determinant:

[(-3-\lambda)(-4-\lambda)(1-\lambda)+(0)(2)(-3)+(2)(-2)(1)]-[(1)(-4-\lambda)(-3)+(0)(2)(1-\lambda)+(2)(-2)(-3-\lambda)]=0\\\\-\lambda^3-6\lambda^2-12\lambda-16=0

and the roots of this polynomial is:

\lambda_1=-4\\\\\lambda_2=-1+i\sqrt{3}\\\\\lambda_3=-1-i\sqrt{3}

hence, the real eigenvalue of the matrix A is -4.

b) The multiplicity of the eigenvalue is 1.

c) The dimension of the eigenspace is 1 (because the multiplicity determines the dimension of the eigenspace)

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Answer:

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Step-by-step explanation:

If the first integer is x, the second is x+1 and the third is x+2.

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It is 31 more than 3 times the smallest: (x+2)*4 = (x)*3+31

When you simplify you get : 4x+8 = 3x+31

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