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3 years ago

Simplify the expression .

Mathematics

1 answer:

san4es73 [151]3 years ago

7 0

Answer:

x^33 y^0 x is to the 33 y is to the 0

Step-by-step explanation:

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Which is greater 1.9 or 0.95

pashok25 [27]

1.9 is greater bc there is a whole number

Hope this helped!!!!

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3 years ago

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At 9:00, Paula has x cups of food in a container for her dog. Paula pours a 2 1/2 cup box of fodd into the container. Then she r

Anestetic [448]

Answer:

X = 21/4 - 7/4 = 14/4 = 7/2 = 3 and 1/2

Step-by-step explanation:

X + (2 and 1/2) - 3/4 = 5 and 1/4

X + 2 and 2/4 - 3/4 = 5 and 1/4 <--- common denominator

X + 10/4 - 3/4 = 21/4

X + 7/4 = 21/4

X = 21/4 - 7/4 = 14/4 = 7/2 = 3 and 1/2

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4 years ago

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Craig hiked for 7/10 mile and stopped to take pics. Then he hiked 25/100 mile. How far did he hike in all

Lena [83]

Craig hiked for 19/20 miles in total

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3 years ago

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A rectangle prism has a height of 4 millimeters and width 5 millimeters. The total surface area is 166 square millimeters, what

Zolol [24]

The answer is 7, 2(7x5) + 2(4x7) + 2(5x4) = 166

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4 years ago

As a follow-up to a report on gas consumption, a consumer group conducted a study of SUV owners to estimate the mean mileage f

kondor19780726 [428]

Answer:

The 95% confidence interval estimate for the mean highway mileage for SUVs is (18.29mpg, 20.91mpg).

Step-by-step explanation:

Our sample size is 96.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 96-1 = 95$

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 95 and 0.025 in the t-distribution table, we have $T = 1.9855$ .

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{5.6}{\sqrt{96}} = 0.57$

Now, we multiply T and s

$M = T*s = 1.9855*0.57 = 1.31$

For the lower end of the interval, we subtract the mean by M. So $19.6 - 1.31 = 18.29$

For the upper end of the interval, we add the mean to M. So $19.6 + 1.31 = 20.91$

The 95% confidence interval estimate for the mean highway mileage for SUVs is (18.29mpg, 20.91mpg).

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4 years ago