Answer:
Step-by-step explanation:
Given
See attachment for illustration
Required
Determine the horizontal distance
The horizontal distance is the distance between the technician and the base of the pole.
Represent this with x.
The relationship between x, 175ft and 25 degrees is represented as:
--- i.e. tan formula
Multiply both sides by x
Make x the subject
--- approximated
<em>The distance is approximately 375.3ft</em>
Um use fled but bfthb 123 tgbs
Let's define the vectors:
U = (4.4)
V = (3.1)
The projection of U into V is proportional to V
The way to calculate it is the following:
Proy v U = [(U.V) / | V | ^ 2] V
Where U.V is the point product of the vectors, | V | ^ 2 is the magnitude of the vector V squared and all that operation by V which is the vector.
We have then:
U.V Product:
U.V = (4,4) * (3,1)
U.V = 4 * 3 + 4 * 1
U.V = 12 + 4
U.V = 16
Magnitude of vector V:
lVl = root ((3) ^ 2 + (1) ^ 2)
lVl = root (9 + 1)
lVl = root (10)
Substituting in the formula we have:
Proy v U = [(16) / (root (10)) ^ 2] (3, 1)
Proy v U = [16/10] (3, 1)
Proy v U = [1.6] (3, 1)
Proy v U = [1.6] (3, 1)
Proy v U = (4.8, 1.6)
Answer:
the projection of (4,4) onto (3,1) is:
Proy v U = (4.8, 1.6)
<span>One nonzero function that satisfies f′(x)=4f(x) can be found by using the constant 'e' and its derivative rules. If we define f(x) = e^(4x), the first derivative f'(x) can be found via the chain rule to be 4*e^(4x) or the 4*f(x) as desired.</span>
